Sorry my points are messed up, but i hope you can see through the mess and get your points graphed!
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i hope this helps!
http://goblues.org/faculty/grantm/files/2015/12/Practice-Test-3.7-Solutions.pdf
I think it's question number three. Sorry if the link dosen't work.
Answer:
The next 3 steps are
Step 4: 
Step 5: 
Step 6: 
Step-by-step explanation:
Given:
Quadratic Equation is
x² + 4x - 6 = 0
To Find:
x = ?
Solution:
Step 1: x2 + 4x = 6
Step 2: x2 + 4x + 4 = 6 + 4
Step 3: (x + 2)2 = 10
Step 4:
Step 5:
Step 6:
The range is {-37,-25,-13,-1}. So you need to figure out what four numbers from this list of numbers (1,2,3,4,5,6,7,8), when applied to this
function, ( f(x)=-6x+11 ), equals these numbers that are in the range {-37,-25,-13,-1}.
So you apply each of these numbers (1,2,3,4,5,6,7,8) into the function (f(x)=-6x+11)
one by one.
f(1)=-6(1)+11=5
f(2)=-6(2)+11= -1
f(3)=-6(3)+11= -7
f(4)=-6(4)+11= -13
f(5)=-6(5)+11= -19
f(6)=-6(6)+11= -25
f(7)=-6(7)+11= -31
f(8)=-6(8)+11= -37
As you can see, f(2),f(4),f(6),and f(8) equal the numbers that are in the range {-37,-25,-13,-1}.
