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Sonja [21]
3 years ago
13

I am trying to get 2/7 into a whole number or a mixed number

Mathematics
1 answer:
kompoz [17]3 years ago
5 0

Answer:

1.3 is the whole number

Step-by-step explanation:

google

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one angle has a measure that is less than 15 than two times a number. a second angle is three times the number. the angles are c
adell [148]

Answer:

27 degrees and 63 degrees

Step-by-step explanation:

Let n be the number.

Angle 1: 2n-15

Angle 2: 3n

If the angles are complementary they add up to 90.

Therefore we can write an equation.

2n-15+3n=90

Combine like terms

5n-15=90

Add 15 to both sides

5n=105

n=21

Now we plug 21 in for n and solve for the angles

Angle 1 = 2(21)-15

Angle 1 = 42-15

Angle 1 = 27

Angle 2 = 3(21)

Angle 2 = 63

4 0
2 years ago
Plz help I need to understand and I don’t
aliina [53]

Answer:

B. 108 \:  {in}^{2}

Step-by-step explanation:

Total surface area of the square pyramid

= 4 times the area of one triangle + Area of square

= 4 \times  \frac{1}{2}  \times 6 \times 6 +  {6}^{2}  \\  \\  = 72 + 36 \\  \\  = 108 \:  {in}^{2}

3 0
3 years ago
Please help, the picture shows what the question is, thanks!
maksim [4K]

Answer:

V≈2412.74

Step-by-step explanation:

5 0
3 years ago
Find two number that are not prime and have a HCF​ of 1?<br> Help me please^°^​
vodomira [7]

Answer:

4,9

Step-by-step explanation:

(1). 4,9 are not prime number

(2) 4=1×2×2

9 = 1×3×3

so,

HCF of 4,9 will be

= 1.

3 0
3 years ago
In abc above,what is the length of ad​
Nezavi [6.7K]

Answer:

B

Step-by-step explanation:

First calculate BD using sine ratio in Δ BCD and the exact value

sin60° = \frac{\sqrt{3} }{2}, thus

sin60° = \frac{opposite}{hypotenuse} = \frac{BD}{BC} = \frac{BD}{12} = \frac{\sqrt{3} }{2} ( cross- multiply )

2BD = 12\sqrt{3} ( divide both sides by 2 )

BD = 6\sqrt{3}

-----------------------------------------------------------

Calculate AD using the tangent ratio in Δ ABD and the exact value

tan30° = \frac{1}{\sqrt{3} } , thus

tan30° = \frac{opposite}{adjacent} = \frac{AD}{BD} = \frac{AD}{6\sqrt{3} } = \frac{1}{\sqrt{3} } ( cross- multiply )

\sqrt{3} AD = 6\sqrt{3} ( divide both sides by \sqrt{3} )

AD = 6 → B

4 0
3 years ago
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