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4 years ago

Please help solve this equation

Mathematics

1 answer:

Luden [163]4 years ago

4 0

Step 1:<span>Multiply both sides by n-6.
step 2: subtract 5n from both sides
step 3: subtract 4 from both sides
step 4: divide both sides by 4
your answer is 17/2</span>

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Find the zeros of the polynomial x^2 + 8x + 16

Scorpion4ik [409]

hey mate,

$x^2 + 8x + 16 = 0$

<=>

$(x+4)^2 = 0$

As we know that $(a+b)^2 = a^2+b^2+2ab$

then

$(x+4)^2 = 0$

<=> (x+4) = 0

<=> x = -4

so there is one solution x = -4

thanks

4 0

3 years ago

Please help!! Andy is 2 year older than jeff. in 5 years the sum of their ages will be 40 years . find their ages now .... provi

ANTONII [103]

Andy's age = x
Jeff's age    = x-2
Andy's age in five years = x+5
Jeff's age in five years    = x-2+5
The sum of their ages in five years = x+5 + x-2+5

   x + 5 + x - 2 + 5 = 40
   2x + 8 = 40
   <u> -8 -8</u>
      2x = 32
     <u> :2 :2</u>
   x = 16
x - 2 = 14

<u>Andy is 16 years old and Jeff is 14 years old</u>

8 0

3 years ago

The probability that a randomly selected elementary or secondary school teacher from a city is a female is , holds a second job

julsineya [31]

Answer:

The probability that an elementary or secondary school teacher selected at random from this city is a female or holds a second job is 0.90.

Step-by-step explanation:

Denote the events as follows:

<em>X</em> = an elementary or secondary school teacher from a city is a female

<em>Y</em> = an elementary or secondary school teacher holds a second job

The information provided is:

P (X) = 0.66

P (Y) = 0.46

P (X ∩ Y) = 0.22

The addition rule of probability is:

$P(A\cup B)=P(A)+P(B)-P(A\cap B)$

Use this formula to compute the probability that an elementary or secondary school teacher selected at random from this city is a female or holds a second job as follows:

$P(X\cup Y)=P(X)+P(Y)-P(X\cap Y)\\=0.46+0.66-0.22\\=0.90$

Thus, the probability that an elementary or secondary school teacher selected at random from this city is a female or holds a second job is 0.90.

4 0

4 years ago

Reverse the two digits of my age, divide by three, add 20, and the result is my age. How many years old am I

lapo4ka [179]

Answer:

48 years old.

Step-by-step explanation:

Let the age be xy or 10x + y.

Reverse the two digits of my age, divide by three, add 20, and the result is my age, convert this to equation:

(10y + x)/3 + 20 = 10x + y
(10y + x)/3 = 10x + y - 20
10y + x = 3(10x + y - 20)
10y + x = 30x + 3y - 60
30x - x + 3y - 10y = 60
29x - 7y = 60

We should consider both x and y are between 1 and 9 since both the age and its reverse are 2-digit numbers.

Possible options for x are:

29x ≥ 7*1 + 60 = 67 ⇒ x > 2, at minimum value of y,

and

29x ≤ 7*9 + 60 = 123 ⇒ x < 5, at maximum value of y.

So x can be 3 or 4.

29*3 - 7y = 60
87 - 7y = 60
7y = 27
y = 27/7, discarded as fraction.

29*4 - 7y = 60
116 - 7y = 60
7y = 56
y = 8

So the age is 48.

6 0

2 years ago

Josh works for The Milkshake Diner. The company wants to know which milkshake flavor is the most popular. Today, he surveyed

AlekseyPX

its b i think please vote me i need points

6 0

3 years ago