The least number of pens each boy can have brought is 60
<h3>How to determine the least number of pen?</h3>
We have:
Vincent = 6 packs
Aidan = 20 boxes
Factorize 6 and 20
6 = 1 * 2 * 3
20 = 1 * 2 * 2 * 5
Multiply all factors
LCM = 1 * 2 * 2 * 3 * 5
Evaluate the product
LCM = 60
Hence, the least number of pens each boy can have brought is 60
Read more about LCM at:
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An example for #1 would be that: 15 is divisible by 3, but not 9. every third multiple of 3, (9, 18, 27,...) is divisible by 9 because 9 is three times the size of 3.
For part two the first number that I thought of is 23.
Real answer
48
*26
------
1,248
Estimate
50
*25
------
1,250
So the answer is..
Estimating is helpful because it makes sure you answered correctly. No, this answer is incorrect and if he had done the estimate he could have seen how he was wrong.
M(h)=5h
that is marcia's number of candles where she makes 5 candles per hour (h)
kevin makes 4 but already did 7 so
k(h)=4h+7
when will they have same numbre of candles?
when will m(h)=k(h)
set equal
5h=4h+7
minus 4h from both sides
1h=7
answer is 7 hours
system of equation is
m=5h
k=4h+7
find what value of h makes m=k true
answer is 7 hours
