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Akimi4 [234]
3 years ago
6

Participating in physical activity can help to reduce stress in all of the following ways EXCEPT:

Physics
2 answers:
MaRussiya [10]3 years ago
5 0
Participating in physical activity can help to reduce stress in all of the following ways except "<span>it causes fatigue and exhaustion" since these two symptoms are almost always associated with prolonged periods of stress.</span>
Allushta [10]3 years ago
3 0

Answer;

C. it causes fatigue and exhaustion

Explanation;

Physical activity boosts up the production of the brain's feel-good neurotransmitters, called endorphins. Exercises or physical activities in almost any form may act as a stress reliever. Being active can boost the feel-good endorphins and distract one from daily worries.

Additionally, exercises help release the stored energy mostly in muscles, release tension, and also enhances the relaxation of muscles.

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A worker pushes a box across the floor to the right at a constant speed with a force of 25N. What
icang [17]

Answer:

Friction between the box and the floor is 25N to the left

Explanation:

There are two forces acting on the box along the horizontal direction:

- The force of push applied by the worker, in the forward direction, F

- The force of friction, F_f, acting in the opposite direction (backward)

So the net force acting on the box is

F_{net}=F-F_f

According to Newton's second law of motion, the net force on an object is equal to the product between its mass (m) and its acceleration (a), so we can write:

F_{net}=ma

And so

F-F_f = ma

However, in this case the box is moving at constant speed; this means that its acceleration is zero:

a=0

Therefore we have:

F-F_f=0

Which means

F_f=F

And since we are told that

F=25 N

This means that the force of friction is also 25 N:

F_f=F=25 N

6 0
4 years ago
Read 2 more answers
_____ variables are manipulated by the experiments
nikitadnepr [17]

Answer:

dependent variables

Explanation:

dependent varibeles are the thing you're measuring and independent variables are the thing you change in the exeriment to get a different dependent variable.

may I get brainliest please? :)

3 0
4 years ago
Consider a uniformly wound solenoid having N=210 turns, length l=0.18 m, and cross-sectional area A = 4.00 cm2. Assume l is much
strojnjashka [21]

Answer:

Explanation:

Number of turns

N = 210turns

Length of solenoid

l = 0.18m

Cross sectional area

A = 4cm² = 4 × 10^-4m²

A. Inductance L?

Inductance can be determined using

L = N²μA/l

Where

μ is a constant of permeability of the core

μ = 4π × 10^-7 Tm/A

A is cross sectional area

l is length of coil

L is inductance

Therefore

L = N²μA / l

L=210² × 4π × 10^-7 × 4 × 10^-4 / 0.18

L = 1.23 × 10^-4 H

L = 0.123 mH

B. Self induce EMF ε?

EMF is given as

ε = -Ldi/dt

Since rate of decrease of current is 120 A/s

Then, di/dt = —120A/s, since the current is decreasing

Then,

ε = -Ldi/dt

ε = - 1.23 × 10^-4 × -120

ε = 0.01478 V

ε ≈ 0.015 V

4 0
3 years ago
The force required to drag several objects across a floor was measured. Calculate the µK for these objects.
olganol [36]

Answer:

Explanation:

Case-A

Block weight W=150\ lb

Friction Force f=30\ lb

and friction force is

f=\mu _kN

where N=normal reaction (Usually equals to weight)

\mu _k=\frac{30}{150}

\mu _K=\frac{1}{5}=0.2

Case-B

Block weight W=20\ N

Friction Force f=5\ N

\mu _k=\frac{f}{N}

\mu _k=\frac{5}{20}=\frac{1}{4}

\mu _k=0.25

Case-C

Block weight W=1500\ lb

Friction Force f=60\ lb

\mu _k=\frac{f}{N}

\mu _k=\frac{60}{1500}

\mu _k=0.04

4 0
4 years ago
Suppose if you whirl a yo-yo about your head in a horizontal circle. in what direction must a force act on the yoyo? What exerts
Rudiy27

Answer:

Direction of force towards the center and string apply the force.      

Explanation:

Lets take

Mass of yo-yo =m

Length of string = L

Angular speed = ω

The radial acceleration a = ω² L

Then the radial force on the yo yo given as

F = m ω² L

Then this radial force act towards the center of the circle formed by yo- yo.The force exerted by string.

So the direction of force towards the center and string apply the force.

4 0
3 years ago
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