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dybincka [34]
3 years ago
15

When a crown of mass 14.7 kg is submerged in water, an accurate scale reads only 13.4 kg. What material is the crown made of?

Physics
1 answer:
Bogdan [553]3 years ago
3 0

Answer:

  ρ = 1.13 10⁴  km/m³

Explanation:

For this exercise we use Newton's equilibrium equation

        B –W + W_scale = 0

Where B is the thrust and W_scale is the balance reading

The push is given by Archimedes' law

        B = ρ_water g V

        B = W- W_scale

        B = m g - m_scale g  

       

Let's calculate

         B = 14.7 9.8 - 13.4 9.8

         B = 12.74 N

         ρ_water g V = 12.74

         V = 12.74 / ρ_water g

         V = 12.74 / 1000 9.8

         V = 0.0013 m³

Let's use density

          ρ = m / V

           

We replace

         ρ = 14.7 / 0.0013

         ρ = 1.13 10⁴  km/m³

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Mashutka [201]

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It cannot be constant because if it does not change and each time it increases its strength and speed.

Explanation:

4 0
2 years ago
an object at rest starts accelerating if it travels 30 meters to end up going 10 m/s what was it’s acceleration
vfiekz [6]

First we have to calculate the time taken to travel the distance 30 m, is

t = \frac{distance}{velocity} = \frac{30 \ m}{10 \ m/s } =  3 \ s.

Now from equation of motion,

v = u + at

Given, v = 10 \ m/s .

As object starts from rest, so  u = 0.

Substituting these values in above equation, we get

 10 \ m/s = 0 + a \times 3 \ s \\\\ a = \frac{10}{3}  = 3.33 \ m/s^2.

Thus, the acceleration is 3.33 \ m/s^2

3 0
3 years ago
A positive charge is moved from point A to point B along an equipotential surface. How much work is performed or required in mov
Nitella [24]

Answer:

No work is performed or required in moving the positive charge from point A to point B.

Explanation:

Lets take

Q= Positive charge which move from  point A to point B along

Voltage difference,ΔV =V₁ - V₂  

The work done

W = Q . ΔV

Given that  charge is moved from point A to point B along an equipotential surface.It means that voltage  difference is zero.

ΔV = 0

So

W = Q . ΔV

W = Q x 0

W= 0 J

So work is zero.

5 0
2 years ago
(i) Calculate the energy, in electron volts, of a photon whose frequency is (a) 620 THz}, (b) 3.10GHz , and(c) 46.0 MHz
DedPeter [7]

The energy in electron volts of the photons that has the following frequencies is as follows:

  1. 620 THz = 2.564eV
  2. 3.10GHz = 1.28 × 10-⁵eV
  3. 46.0 MHz = 1.902 × 10-⁷eV

<h3>How to calculate energy?</h3>

The energy of a photon can be calculated using the following formula:

E = hf

Where;

  • E = energy
  • h = Planck's constant (6.626 × 10-³⁴ J/s)
  • f = frequency

First, we convert the frequencies to hertz as follows;

  • 620THz = 6.2 × 10¹⁴Hz
  • 3.10GHz = 3.1 × 10⁹Hz
  • 46.0MHz = 4.6 × 10⁷Hz

  1. E = 6.626 × 10-³⁴ × 6.2 × 10¹⁴ = 2.564eV
  2. E = 6.626 × 10-³⁴ × 3.1 × 10⁹ = 1.28 × 10-⁵eV
  3. E = 6.626 × 10-³⁴ × 4.6 × 10⁷ = 1.902 × 10-⁷eV

Learn more about energy of a photon at: brainly.com/question/2393994

#SPJ1

6 0
1 year ago
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