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dybincka [34]
3 years ago
15

When a crown of mass 14.7 kg is submerged in water, an accurate scale reads only 13.4 kg. What material is the crown made of?

Physics
1 answer:
Bogdan [553]3 years ago
3 0

Answer:

  ρ = 1.13 10⁴  km/m³

Explanation:

For this exercise we use Newton's equilibrium equation

        B –W + W_scale = 0

Where B is the thrust and W_scale is the balance reading

The push is given by Archimedes' law

        B = ρ_water g V

        B = W- W_scale

        B = m g - m_scale g  

       

Let's calculate

         B = 14.7 9.8 - 13.4 9.8

         B = 12.74 N

         ρ_water g V = 12.74

         V = 12.74 / ρ_water g

         V = 12.74 / 1000 9.8

         V = 0.0013 m³

Let's use density

          ρ = m / V

           

We replace

         ρ = 14.7 / 0.0013

         ρ = 1.13 10⁴  km/m³

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Explanation:

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A musical note has a frequency of 512 Hz. If the wavelength of the note is 0.685 m, what is the speed of the sound of that note?
riadik2000 [5.3K]

Answer:

350.72 m/s

Explanation:

Formula for velocity of wave is;

v = fλ

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v is speed

f is frequency

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We are given;

f = 512 Hz

λ = 0.685 m

Thus;

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5 0
2 years ago
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goblinko [34]

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4 0
3 years ago
Read 2 more answers
A dart is thrown at a dartboard 3.66 m away. When the dart is released at the same height as the center of the dartboard, it hit
lapo4ka [179]

Answer:

The  angle is  \theta  =  15.48^o

Explanation:

From the question we are told that  

     The distance of the dartboard from the dart is  d  =  3.66  \ m

     The time taken is  t =  0.455 \ s

   

The  horizontal component of the speed of the dart is mathematically represented as

      u_x =  ucos \theta

where u is the the velocity at dart is lunched

  so

      distance =  velocity \ in \ the\  x-direction  *  time

substituting values

      3.66 =   ucos  \theta *  (0.455)

 =>   ucos \theta =  8.04  \ m/s

From projectile kinematics the time taken by the dart can be mathematically represented as

         t  =  \frac{2usin \theta }{g}

=>    usin \theta =  \frac{g  * t}{2 }

       usin \theta =  \frac{9.8  * 0.455}{2 }

      usin \theta = 2.23

=>   tan \theta =  \frac{usin\theta }{ucos \theta }  =  \frac{2.23}{8.04}

       \theta  =  tan^{-1} [0.277]

      \theta  =  15.48^o

     

4 0
3 years ago
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