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ZanzabumX [31]
4 years ago
5

When landing after a spectacular somersault, a 40.5 kg gymnast decelerates by pushing straight down on the mat. Calculate the fo

rce she must exert if her deceleration is 7.00 times the acceleration due to gravity in Newtons.
Physics
1 answer:
monitta4 years ago
4 0

Answer:

F= = 3.18 * 10^3 N

Explanation:

information given:

m= 40.5 kg

a= seven times gravity so we have

a= 7 g

where

gravity = g  =9.8 m/s2

F= m*a

F= (40.5) * 7g

a = 7 g = (7) (9.8) = 68.6 m/s2

There are two forces acts on gymnsat

Where ,w is the weight of Gymnsat

F(net) = F - mg

F- mg = ma

F = mg+ma

so  

F=  m ( g + a)

F = (40.5) [9.8+ 68.6 ]

F = 3.18 * 10^3 N

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Plz help I will give brainly to the correct answer
Tresset [83]

Answer:

D. x-rays

Explanation:

Lower frequency: Radio waves, microwaves and infrared have lower frequency than visible light. Shorter wavelength: Ultraviolet, x-rays and gamma rays have a shorter wavelength than visible light.

4 0
3 years ago
Which of the following statements is/are true?Check all that apply.a. A conservative force permits a two-way conversion between
Eddi Din [679]

Answer:

a). A conservative force permits a two-way conversion between kinetic and potential energies.

TRUE

Because there is no energy loss in presence of conservative forces so energy conversion in two ways are possible.

b). A potential energy function can be specified for a conservative force.

TRUE

negative gradient of potential energy is equal to conservative force

F = -\frac{dU}{dr}

c). A non-conservative force permits a two-way conversion between kinetic and potential energies.

FALSE

here energy is lost against non-conservative forces

d). The work done by a conservative force depends on the path taken.

FALSE

work done by conservative force is independent of path

e). The work done by a non-conservative force depends on the path taken.

TRUE

work done by non conservative forces depends on path.

f). A potential energy function can be specified for a non-conservative force.

FALSE

It is not defined for non conservative forces

3 0
3 years ago
15) On a cold day, you take in 4.2 L (i.e., 4.2 x 10-3 m3) of air into your lungs at a temperature of 0°C. If you hold your brea
Rudiy27

Answer:

4.8L ( i.e 4.8 x 10^-3 m3)

Explanation:

Step 1:

Data obtained from the question.

Initial volume (V1) = 4.2L

Initial temperature (T1) = 0°C

Final temperature (T2) = 37°C

Final volume (V2) =?

Step 2:

Conversion of celsius temperature to Kelvin temperature. This is illustrated below

K = °C + 273

T1 = 0°C = 0°C + 273 = 273K

T2 = 37°C = 37°C + 273 = 310K

Step 3:

Determination of the final volume.

Since the pressure is constant,

Charles' Law equation will be applied as shown below:

V1 /T1 = V2/T2

4.2/273 = V2 /310

Cross multiply to express in linear form

273 x V2 = 4.2 x 310

Divide both side by 273

V2 = (4.2 x 310)/273

V2 = 4.8L ( i.e 4.8 x 10^-3 m3)

Therefore, the volume of the air in the lungs at that point is 4.8L ( i.e 4.8 x 10^-3 m3)

3 0
4 years ago
An automobile battery has an emf of 12.6 V and an internal resistance of 0.0600 . The headlights together present equivalent res
murzikaleks [220]

Answer:

(a) V=11.86\ V

(b) V=9.76\ V

Explanation:

<u>Electric Circuits</u>

Suppose we have a resistive-only electric circuit. The relation between the current I and the voltage V in a resistance R is given by the Ohm's law:

V=R.I

(a) The electromagnetic force of the battery is \varepsilon =12.6\ V and its internal resistance is R_i=0.06\ \Omega. Knowing the equivalent resistance of the headlights is R_e=5.2\ \Omega, we can compute the current of the circuit by using the Kirchhoffs Voltage Law or KVL:

\varepsilon=i.R_i+i.R_e=i.(R_i+R_e)

Solving for i

\displaystyle i=\frac{\varepsilon}{ R_i+R_e}=\frac{12}{0.06+5.2}=2.28\ A

i=2.28\ A

The potential difference across the headlight  bulbs is

V=\varepsilon  -i.R_i=12\ V-2.28\ A\cdot 0.06\ \Omega=11.86\ V

V=11.86\ V

(b) If the starter motor is operated, taking an additional 35 Amp from the battery, then the total load current is 2.28 A + 35 A = 37.28 A. Thus the output voltage of the battery, that is the voltage that the bulbs have is

V=\varepsilon  -i.R_i=12\ V-37.28\ A\cdot 0.06\ \Omega=9.76\ V

5 0
3 years ago
Modern scientists say that electrons are found in a ...
bulgar [2K]
I think it might be a or d i hope i have helped :)
8 0
4 years ago
Read 2 more answers
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