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3 years ago

Select the correct answer.

Physics

1 answer:

Dovator [93]3 years ago

3 0

Answer:

D. Mars is a long distance away

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A chemical is always the same thing as an element .<br><br> True <br> False

olya-2409 [2.1K]

That would be false

Hope this helps :)

3 0

3 years ago

Read 2 more answers

A sun-like star is barely visible to naked-eye observers on earth when it is a distance of 7.0 light years, or 6.6 * 1016 m, awa

igomit [66]

Answer:

At a distance of 1376.49 candle emits 0.2 watt power

Explanation:

Distance between Sun and earth $6.6\times 10^{16}m$

Sun emits a power of $P=3.8\times 10^{26}watt$

Power emitted by candle = 0.20 watt

We know that brightness is given by

$B=\frac{P}{4\pi d^2}$

So $\frac{3.8\times 10^{26}}{4\pi (6\times 10^{16})^2}=\frac{0.20}{4\pi d^2}$

$3.8\times 10^{26}d^2=7.2\times 10^{32}$

$d^2=1.89\times 10^6$

$d=1376.49m$

So at a distance of 1376.49 candle emits 0.2 watt power

3 0

3 years ago

A steel beam that is 6.50 m long weighs 336 N. It rests on two supports, 3.00 m apart, with equal amounts of the beam extending

FinnZ [79.3K]

Answer:

Explanation:

When beam is balanced and not rotating with Suki standing on it , let reaction force on the supports be R₁ and R₂. Then

R₁ +R₂ = 336 + 590

= 929

Now the moment beam begins to tip , reaction on distant support R₁ = 0

only R₂ will exists on the support near to Suki.

Taking torque about this support of weight of beam acting from the middle point and weight of suki of 590N ,who is x distance from the support towards the other end.

336 x 1.5 = 590 x

x = .85 m

ie , from second support , Suki can not go beyond a distance of .85 m towards the second end.

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3 years ago

A 4.50-volt personal stereo uses 1950 joules of electrical energy in one hour. what is the electrical resistance of the personal

saveliy_v [14]

The stereo uses an energy of $E=1950 J$ in a time $t=1 h=3600 s$ , therefore the power of the stereo is given by
$P= \frac{E}{t}= \frac{1950 J}{3600 s}=0.54 W$

We also know that the power of an electrical device is related to its voltage, V, and its resistance, R, by the following equation
$P= \frac{V^2}{R}$
therefore, we can rearrange the equation to calculate the resistance of the stereo:
$R= \frac{V^2}{P}= \frac{(4.5 V)^2}{0.54 W}=37.5 \Omega$

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4 years ago

Sound waves are also called compression waves. This means that as the wave travels through air, the ________ increases and decre

Nuetrik [128]

I believe the answer is pressure. hope this helps

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3 years ago