Answer:
h = 20 m
Explanation:
height (h) = 10 m
potential energy (PE) = 50 J
kinetic energy (KE) = 50 J
what is the maximum height reached by the ball
- At 10 meters above the ground potential energy (PE) = 50 J
mgh = 50
recall that height (h) = 10
mg (10) = 50
mg = 5 .....equation 1
- The total energy of the system at 10 meters is given as PE + KE = 100 Joules. From the conservation of energy the total energy in the system still remains the same at the maximum height, this is because energy can neither be created nor destroyed but can be transformed from one form to another.
- At the maximum height the velocity (v) of the system is 0, which means all its kinetic energy (KE) is converted to potential energy. Therefore the system consist only of potential energy.
KE + PE = 100
+ mgh = 100 J
velocity (v) = 0 at maximum height therefore
0 + mgh = 100
mgh = 100
recall that mg = 5 from equation 1, therefore
5h = 100
h = 20 m
Here we can say that net speed against the wind is given by
![V_{plane} - v_{wind} = \frac{distance}{time}](https://tex.z-dn.net/?f=V_%7Bplane%7D%20-%20v_%7Bwind%7D%20%3D%20%5Cfrac%7Bdistance%7D%7Btime%7D)
![V_{plane} - v_{wind} = \frac{3624}{6}](https://tex.z-dn.net/?f=V_%7Bplane%7D%20-%20v_%7Bwind%7D%20%3D%20%5Cfrac%7B3624%7D%7B6%7D)
![V_{plane} - v_{wind} = 604 mph](https://tex.z-dn.net/?f=V_%7Bplane%7D%20-%20v_%7Bwind%7D%20%3D%20604%20mph)
also if it is moving along the direction of wind we will have
![V_{plane} + v_{wind} = \frac{distance}{time}](https://tex.z-dn.net/?f=V_%7Bplane%7D%20%2B%20v_%7Bwind%7D%20%3D%20%5Cfrac%7Bdistance%7D%7Btime%7D)
![V_{plane} + v_{wind} = \frac{4764}{6}](https://tex.z-dn.net/?f=V_%7Bplane%7D%20%2B%20v_%7Bwind%7D%20%3D%20%5Cfrac%7B4764%7D%7B6%7D)
![V_{plane} + v_{wind} = 794 mph](https://tex.z-dn.net/?f=V_%7Bplane%7D%20%2B%20v_%7Bwind%7D%20%3D%20794%20mph)
now add the above two equations we will have
![V_{plane} = 699 mph](https://tex.z-dn.net/?f=V_%7Bplane%7D%20%3D%20699%20mph)
also we can say
![v_{wind} = 95 mph](https://tex.z-dn.net/?f=v_%7Bwind%7D%20%3D%2095%20mph)
<h3>
Answer:</h3>
7000 Joules
<h3>
Explanation:</h3>
We are given;
- The mass of an object = 100 kg
But, Force = mass × g (taking g as 10 N/kg)
Assuming we are given the distance moved by the object as 7 m
We can calculate the work done by the force
We need to know that;
Work done = Force × distance
Therefore;
Work done = 1000 N × 7 m
= 7000 Joules
Therefore, the work done by the force is 7000 Joules
Answer
Initial radius of the artery is (1.1 cm) / 2 = 0.55 cm
final radius of the artery is (0.90 cm) / 2 = 0.45 cm
initial velocity of the blood is 17 cm/s
Using equation of continuity is
A₁v₁=A₂v₂
π r₁² x v₁ = π r₂² x v₂
r₁² x v₁ = r₂² x v₂
0.55² x 17 =0.45² x v₂
v₂=25.39 cm/s
Bernoulli's equation is
rho is the density of blood = 1060 kg/m^3
The potential energy of an object is defined as the energy it harnesses as a result of the downwards pull of gravity. The acceleration due to gravity is equivalent to 9.8 m/s^2. Potential energy can be calculated using the formula: PE = mgz
where:
m = mass
g = acceleration due to gravity
z = height
Therefore, for this problem, the PE = 70(9.8)(8) = 5488 Joules