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allsm [11]
3 years ago
11

2 objects have a total momentum of 400kg m/s, they collide. Object A’s mass is5kg & object B’s mass is 11kg. After the colli

sion Object B is moving at 15m/s.What is the velocity of Object A AFTER the collision?
Physics
1 answer:
ss7ja [257]3 years ago
3 0

Answer:

Explanation:

We shall apply law of conservation of momentum .

Momentum before collision = momentum after collision .

Momentum before collision = 400 kg m/s

Momentum after collision = 5  x v + 11 x 15

where v is velocity of A after the collision .

5  x v + 11 x 15 = 400

5 v = 400 - 165

5v = 235

v = 47 m /s .

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A solid uniform cylinder is rolling without slipping. What fraction of its kinetic energy is rotational?
tester [92]

Answer:

Explanation:

Let m be the mass of cylinder and r be the radius. It is moving with velocity v and angular velocity is ω. Let I be the moment of inertia of the cylinder.

I = 0.5 mr²

Total kinetic energy, T = 0.5 mv² + 0.5 Iω²

T = 0.5 (mv² + 0.5 mr²ω²)

v = rω

So, T = 0.5 (mv² + 0.5 mv²) = 0.75 mv²

Rotational kinetic energy is

R = 0.5 Iω² = 0.5 x 0.5 mr²ω²

R = 0.25 mv²

So, R / T = 0.25 / 0.75 = 1/3

5 0
3 years ago
A ball is projected at an angle of elevation of 60 ° with an initial velocity of 120m/s.calculate
Mrac [35]

Explanation:

It is given that,

The angle of projection is 60 degrees

Initial velocity of the ball is 120 m/s

We need to find the time taken to get to the maximum height and the time of flight.

Time taken to reach the maximum height is given by :

T=\dfrac{u^2\sin^2\theta}{2g}

g is acceleration due to gravity

T=\dfrac{(120)^2\times \sin^2(60)}{2\times 10}\\\\T=540\ s

(ii) Time of flight,

t=\dfrac{2u\sin\theta}{g}

So,

t=\dfrac{2\times 120\times \sin(60)}{10}\\\\t=20.78\ s

Hence, this is the required solution.

3 0
3 years ago
Why does a comet's tail point away from the Sun? 1Choice 1 The solar wind blows the tail away from the Sun. 2 It is being pulled
AnnyKZ [126]

Choice 1

The Sun's radiation and solar wind cause the dust and gas around the comet (coma) to stretch the coma. The solar wind electromagnetically blows the ions in the coma away.

4 0
3 years ago
An old millstone, used for grinding grain in a gristmill, is a solid cylindrical wheel that can rotate about its central axle wi
MAXImum [283]

Answer:

The answer is I=70,513kgm^2

Explanation:

Here we will use the rotational mechanics equation T=Ia, where T is the Torque, I is the Moment of Inertia and a is the angular acceleration.

When we speak about Torque it´s basically a Tangencial Force applied over a cylindrical or circular edge. It causes a rotation. In this case, we will have that T=Ft*r, where Ft is the Tangencial Forge and r is the radius

Now we will find the Moment of Inertia this way:

Ft*r=I*a -> (Ft*r)/(a) = I

Replacing we get that I is:

I=(200N*0,33m)/(0,936rad/s^2)

Then I=70,513kgm^2

In case you need to find extra information, keep in mind the Moment of Inertia for a solid cylindrical wheel is:  

I=(1/2)*(m*r^2)

4 0
3 years ago
calculate the distance a plane flies on a 7.95 hour flight from Chicago to London. Assume a constant speed of 800.0 km/h
soldier1979 [14.2K]

Answer:

6360 km

Explanation:

Use the kinematics equation x=v_ot+\frac{1}{2}at^2.  We are given t = 7.95 hours and a = 0 m/s^2 (constant speed means there is no acceleration).  Solve for x.

x=(800)(7.95)+\frac{1}{2}(0)(7.95^2)\\x=6360 \ km

4 0
3 years ago
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