2 objects have a total momentum of 400kg m/s, they collide. Object A’s mass is5kg & object B’s mass is 11kg. After the colli
1 answer:
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Explanation:
It is given that,
The angle of projection is 60 degrees
Initial velocity of the ball is 120 m/s
We need to find the time taken to get to the maximum height and the time of flight.
Time taken to reach the maximum height is given by :
g is acceleration due to gravity
(ii) Time of flight,
So,
Hence, this is the required solution.
Answer:
The answer is I=70,513kgm^2
Explanation:
Here we will use the rotational mechanics equation T=Ia, where T is the Torque, I is the Moment of Inertia and a is the angular acceleration.
When we speak about Torque it´s basically a Tangencial Force applied over a cylindrical or circular edge. It causes a rotation. In this case, we will have that T=Ft*r, where Ft is the Tangencial Forge and r is the radius
Now we will find the Moment of Inertia this way:
->
Replacing we get that I is:
Then
In case you need to find extra information, keep in mind the Moment of Inertia for a solid cylindrical wheel is:
Answer:
6360 km
Explanation:
Use the kinematics equation . We are given t = 7.95 hours and a = 0 m/s^2 (constant speed means there is no acceleration). Solve for x.