2 objects have a total momentum of 400kg m/s, they collide. Object A’s mass is5kg & object B’s mass is 11kg. After the colli
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Answer:
V_{average} = , V_{average} = 2 V
Explanation:
he average or effective voltage of a wave is the value of the wave in a period
V_average = ∫ V dt
in this case the given volage is a square wave that can be described by the function
V (t) =
to substitute in the equation let us separate the into two pairs
V_average =
V_average =
V_{average} =
we evaluate V₀ = 4 V
V_{average} = 4 / 2)
V_{average} = 2 V
Answer:
3.59 m/s
Explanation:
We are given that
Mass of lineman,m=85 kg
Mass of receiver,m'=90 kg
Speed of receiver,v'=5.8 m/s
Speed of lineman,v=4.1 m/s
We have to find the their velocity immediately after the tackle.
Initial momentum,
According to law of conservation of momentum
Initial momentum=Final momentum=