A square loop of side length a =2.9 cm is placed a distance b = 1.2 cm from a long wire carrying a current that varies with time
at a constant rate, i.e. I(t) = Qt, where Q = 2.3 A/s is a constant. show answer Correct Answer 25% Part (a) Find an expression for the magnetic field due to the wire as a function of time t at a distance r from the wire, in terms of a, b, Q, t, r, and fundamental constants. B(t) = ( μ0 Q t )/( 2 π r ) Part (b) What is the magnitude of the flux through the loop? Select the correct expression. Part (c) If the loop has a resistance of 2.5 Ω, how much induced current flows in the loop?
B = ( μ₀ / 4π ) x 2 I / r ( I is current through the wire )
= (μ₀ Q t ) / ( 2 π r ) [ I = Q t ]
b ) Magnetic field will change through the length of the square shaped loop . So we shall have to take the help of integration to calculate the flux through the loop.
