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const2013 [10]
3 years ago
5

Factor completely 20x^3y + 30x^2y^2.

Mathematics
1 answer:
weqwewe [10]3 years ago
6 0

Answer:

10x^2 y(2x + 3y)

Step-by-step explanation:

20x^3 y + 30x^2 y^2.

Factor 10x^2y out of 20x^3y.

10x^2 y (2x) + 30x^2 y^2  

Factor 10x^2y out of 30x^2y^2.

10x^2 y (2x) + 10x^2 y (3y)  

Factor 10x^2y out of 10x^2 y (2x) + 10x^2 y (3y).

10x^2 y(2x + 3y)

you factor out 10x^2y from both side which you will then get 10x^2 y (2x) + 10x^2 y (3y)  than you factor out 10x^2y again and get 10x^2 y(2x + 3y)  your third option

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Andre45 [30]

Answer:

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Step 1: Subtract 18 from both sides.

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Step 3: Set factors equal to 0.

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7 0
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