Id day B. 2.2 kilometers, but its just an estimate
Answer:12.5 seconds
Step-by-step explanation:hconsidering Runner 1 with a speed of 10m/s
and Runner 2 with a speed of 4 m/s
the equation of displacement for a uniform movement is
x=V*t
so x1=V1*t
and x2=V2*t
and the problem condition is x2=x1+75m
so we proceed to solve the equations.
from equation 2 t=x2/V2
substituting in equation 1 we have
x1=V1(x2/V2) and then the 3 equation
x1=V1((x1+75m)/v2
finally x1=75*(V1/(V2-V1)) =75*(10/(10-4))=125m
then t=(x1/v1)=125/10=12.5 seconds
Answer: 1.75 Days
Step-by-step explanation: I don't really know how to explain this?
Tell me if this was helpful :D
Answer:
240 inches squared.
Step-by-step explanation:
To find the surface area, find the area of each triangle and the square. Then add all the areas together.
Triangle - A = 1/2bh where b = 8 and h = 11. So the area of 1 triangle is A = 1/2*8*11 = 44. Since there are 4 triangles then 4*44 = 176 inches squared.
Square - A = s^2 where s = 8. So the area of the square is A = 2^2 = 8^2 = 64.
So all the areas add together to 176 + 64 = 240.
ANSWER: A. 46
SOLUTION
Given that Q is equidistant from the sides of TSR
m∠TSQ = m ∠QSR
To solve for x
m∠TSQ = 3x + 2
m ∠QSR = 8x – 33
Since m∠TSQ = m ∠QSR
3x + 2 = 8x – 33
Add 33 to both sides
3x + 2 + 33 = 8x – 33 + 33
3x + 35 = 8x
8x = 3x + 35
Subtract 3x from both sides
8x – 3x = 3x – 3x + 35
5x = 35
Divide both sides by 5
x = 7
Since m∠TSQ = 3x + 2, and x = 7
m∠TSQ = (3*7) + 2
m∠TSQ = 21 + 2
m∠TSQ = 23
To solve for RST
Given that Q is equidistant from the sides of RST
m∠RST = m∠TSQ + m ∠QSR
Since m∠TSQ = m ∠QSR
m∠RST = 2m∠TSQ = 2m ∠QSR
Ginen, m∠RST = 2m∠TSQ
m∠TSQ = 23
m∠RST = 2(23)
m∠RST = 46
