I need help with numbers 20,21,and22
1 answer:
Answer:
20) the answer is -43
21) the answer is 25
22)the answer is -5
Step-by-step explanation:
20) 
n=-7
p=-6
we have:

21) mp-(p-(m-n))
m= -1 n=-6 p=-10
-1*-10-(-10-(-1-(-6)))
10-(-10-(5))
10-(-15)
10+15=25
22) 
m=1 n=5
1- 
1- 2/2 -5
1-1-5 =-5
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Step-by-step explanation:
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If <em>z</em> ⁷ = 128<em>i</em>, then there are 7 complex numbers <em>z</em> that satisfy this equation.

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

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