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zavuch27 [327]
3 years ago
8

Why do we calculate a triangular prism and rectangular pris with the same formula?

Mathematics
1 answer:
katovenus [111]3 years ago
5 0
Is it the same formula?What formulas are you using?
Also, are you calculating area or volume?
Source:http://www.1728.org/triprism.htm
http://www.1728.org/recsolid.htm



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Mark is in training for a bicycle race. He needs to ride 50 kilometers a week as part of his training. He rode 18.23 kilometers
kirill115 [55]

the answer is B-about 18km


7 0
3 years ago
Explain why the expression 9x^3+1/2x^2+3x^-1 is not a polynomial
Nastasia [14]

Answer:

The given expression can't be expressed in polynomial form. Hence, it is not a polynomial.

Step-by-step explanation:

P(x,n) is a polynomial of nth degree if it is of the form,

P(x,n) = a_{0} + a_{1}x + a_{2}x^{2} + a_{3}x^{3} + ......... +a_{n}x^{n}

where n is a finite positive integer and n ∈ N

and 'a_{i}'s are fixed but otherwise arbitrary constants ∀  i = 0(1)n .

Now, the given expression is,

9x^{3} + \frac {1}{2x^{2}} + 3x^{-1}

which  doesn't fit in the above form. Hence, it is not a polynomial.

4 0
3 years ago
Please help !
nadya68 [22]

Answer:

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r(5)= -12

6 0
2 years ago
A beachball has a surface area of about 615.75 square meters. Find the
Genrish500 [490]

Answer: The radius of the ball is 7 meters.

Step-by-step explanation:

Hi, to answer this question we have to apply the next formula:

Surface area of a sphere: 4 π r^2

Replacing with the value given:

615.75 = 4 π r^2

Solving for r (radius):

615.75 /4π= r^2

√(615.75 /4π) =r

r = 6.99 = 7m (rounded)  

The radius of the ball is 7 meters.

Feel free to ask for more if needed or if you did not understand something.  

5 0
3 years ago
What is the peremeter of this polygon? (With picture)
lyudmila [28]
Check the picture below.

so.. simply, use the distance formula, to get their length an add them up, and that's the perimeter of the polygon.


\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
&({{ -1}}\quad ,&{{ 2}})\quad 
%  (c,d)
&({{ 2}}\quad ,&{{ 4}})\\
&({{ 2}}\quad ,&{{ 4}})\quad 
%  (c,d)
&({{ 3}}\quad ,&{{ -2}})\\
&({{ 3}}\quad ,&{{ -2}})\quad 
%  (c,d)
&({{ -2}}\quad ,&{{ -3}})\\
&({{ -2}}\quad ,&{{ -3}})\quad 
%  (c,d)
&({{ -1}}\quad ,&{{ 2}})
\end{array}\qquad 
%  distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}

\bf -------------------------------\\\\
d=\sqrt{[2-(-1)]^2+(4-2)^2}\implies d=\sqrt{(2+1)^2+(2)^2}
\\\\\\
d=\sqrt{3^2+2^2}\implies \boxed{d=\sqrt{13}}\\\\
-------------------------------\\\\
d=\sqrt{(3-2)^2+(-2-4)^2}\implies d=\sqrt{1^2+(-6)^2}\implies \boxed{d=\sqrt{37}}\\\\
-------------------------------\\\\
d=\sqrt{(-2-3)^2+[-3-(-2)]^2}\implies d=\sqrt{(-5)^2+(-3+2)^2}
\\\\\\
d=\sqrt{(-5)^2+(-1)^2}\implies \boxed{d=\sqrt{26}}

\\\\
-------------------------------\\\\
d=\sqrt{[-1-(-2)]^2+[2-(-3)]^2}\implies d=\sqrt{(-1+2)^2+(2+3)^2}
\\\\\\
d=\sqrt{(1)^2+(5)^2}\implies \boxed{d=\sqrt{26}}

so, those are their lengths, sum them all up, that's the polygon's perimeter.

4 0
3 years ago
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