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svetoff [14.1K]
3 years ago
9

4. Solve for the missing variable. (The angle at the bottom is 97°)

Mathematics
1 answer:
julsineya [31]3 years ago
4 0

Answer:

ghgetevdye bgeygdyeb fvwshdv sb dj ywud eg  

Step-by-step explanation:

jdnujdm

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I need the answer fast I am in schoool pls
Stolb23 [73]

Answer:

288

Step-by-step explanation:

To solve, we need to find the area of the four triangle sides and add that to the square base's area.

Area of triangle sides: base * height * 0.5

Area of square base: base * height

Substitute the values

8 * 14 * 0.5 = 56

There are four of these sides, so the area of all the triangles is 224.

The square base is 8 * 8, or 64

Add these two values together.

64 + 224 = 288

Thus, the answer is 288

8 0
2 years ago
the length of a rectangle is 6in.more than than its width .Its area is 50 sq.in Find the width of the rectangle....
yulyashka [42]
L=6+W
A=LW
sub 6+W for L
A=(6+W)(W)
expand
oh, A=50
50=W²+6W
minus 50 both sides
0=W²+6W-50
we gots to use quadratic formula
for
aW²+bW+c=0
W=\frac{-b+/- \sqrt{b^2-4ac} }{2a}
we got
a=1
b=6
c=-50


W=\frac{-(6)+/- \sqrt{(6)^2-4(1)(-50)} }{2(1)}
W=\frac{-6+/- \sqrt{36+200} }{2}
W=\frac{-6+/- \sqrt{236} }{2}
W=\frac{-6+/- 2\sqrt{59} }{2}
W=-3+/- \sqrt{59}

W=-3+ \sqrt{59} or W=-3- \sqrt{59}
aprox
W=-10.6811 or W=4.68115
can't be negative width

width=4.68115 or -3√59
7 0
3 years ago
Plz help me with this
Agata [3.3K]

Answer:

It's the first option.

Step-by-step explanation:

y = cos x transformed  to cos (x - π/2) moves  the graph  π/2 units to the right.

Multiplying by 3 to give 3 cos(x -  π/2)  stretches the graph 3 units parallel to the y-axis and adding 3 to this moves the graph up 3 units.

So the required equation is y = 3(cos x -  π/2) + 3.

3 0
3 years ago
Which list of vaules is ordered from lest to greastest?
inessss [21]
The answer is B it's ordered from least to greatest
6 0
3 years ago
Read 2 more answers
Marissa has a photograph that measures 2 in. by 4 in. She has mounted the picture on a mat so that there is a border that measur
Ket [755]

Step-by-step explanation:

The initial image of the photo is 2 in by 4 in.  The mat is 4 in by 6 in.

The new image is dilated by a scale of 2.  So we double the dimensions.  The new photo is 4 in by 8 in.  The new mat is 8 in by 12 in.

7 0
3 years ago
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