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svetoff [14.1K]
3 years ago
9

4. Solve for the missing variable. (The angle at the bottom is 97°)

Mathematics
1 answer:
julsineya [31]3 years ago
4 0

Answer:

ghgetevdye bgeygdyeb fvwshdv sb dj ywud eg  

Step-by-step explanation:

jdnujdm

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251 = 148 + j how do you solve this
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In order to arrive at the answer, take the total (251) and subract it by 148.  J = 103
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Joe bought 20 ounces of nuts at the store. How much is this in pounds? Write your answer as a whole number or a mixed number in
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Of 585 samples of seafood purchased from various kinds of food stores in different regions of a country and genetically compared
Dafna1 [17]

Answer:

a) The 99% confidence interval is from 14.8% to 23.2%.

b) The confidence interval tells us that the true proportion of mislabeled is within 14.8% and 23.2%, with a 99% confidence. In other words, if we take samples of the same size, 99% of the samples will have a proportion within 0.148 and 0.232.

c) The confidence interval calculation take into account the sample size, so the width (or precision) of the interval depends on the sample size.

The only criticism that could be analyzed is to see if the sample is representative of the population.

Step-by-step explanation:

a) We have to calculate a 99% confidence interval for the proportion.

The sample proportion is p=0.19.

 

The standard error of the proportion is:

\sigma_p=\sqrt{\dfrac{p(1-p)}{n}}=\sqrt{\dfrac{0.19*0.81}{585}}\\\\\\ \sigma_p=\sqrt{0.000263}=0.016

The critical z-value for a 99% confidence interval is z=2.576.

The margin of error (MOE) can be calculated as:

MOE=z\cdot \sigma_p=2.576 \cdot 0.02=0.042

Then, the lower and upper bounds of the confidence interval are:

LL=p-z \cdot \sigma_p = 0.19-0.042=0.148\\\\UL=p+z \cdot \sigma_p = 0.19+0.042=0.232

The 99% confidence interval for the population proportion is (0.148, 0.232).

5 0
3 years ago
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