Answer:
0.6563 or 65.63% of brook trout caught will be between 12 and 18 inches
Step-by-step explanation:
Mean trout length (μ) = 14 inches
Standard deviation (σ) = 3 inches
The z-score for any given trout length 'X' is defined as:
e interval
For a length of X =12 inches:

According to a z-score table, a score of -0.6667 is equivalent to the 25.25th percentile of the distribution.
For a length of X =18 inches:

According to a z-score table, a score of 1.333 is equivalent to the 90.88th percentile of the distribution.
The proportion of trout caught between 12 and 18 inches, assuming a normal distribution, is the interval between the equivalent percentile of each length:

Answer:
I think it's A
Step-by-step explanation:
Answer:
408.46cm^2
Step-by-step explanation:
Given data
Height= 13cm
Diameter= 10cm
Radius= D/2= 10/2= 5cm
The area of the curved surface will be = 2πr × h = 2πrh
substitute
Area of the curved surface = 2πrh= 2*3.142*5*13
Area of the curved surface = 2πrh= 408.46cm^2
Hence the area of the curve surface is 408.46cm^2