What is the probability that a point chosen at random in the given figure will be inside the smaller square?
1 answer:
I have to interpret that:
1) the smaller square has side length = 3 cm
2) the bigger square has side length = 5 cm
3) the smaller square is completely inside the bigger square.
4) the points cannot be outside the bigger square
Under those assumptions the probability that a point is inside the smaller square is
P (inside the smaller square) = area of the smaller square / area of the bigger square
P (inside the smaller squere) = (3cm)^2 / (5cm)^2 = 9 / 25
Answer: 9 / 25
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Step-by-step explanation:
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= -4.5 -5
= 9.5
2 -------- f(x) = 3(2) - 5
= 6 -5
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4 -------- f(x) = 3(4) - 5
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Step-by-step explanation: