What is the probability that a point chosen at random in the given figure will be inside the smaller square?
1 answer:
I have to interpret that:
1) the smaller square has side length = 3 cm
2) the bigger square has side length = 5 cm
3) the smaller square is completely inside the bigger square.
4) the points cannot be outside the bigger square
Under those assumptions the probability that a point is inside the smaller square is
P (inside the smaller square) = area of the smaller square / area of the bigger square
P (inside the smaller squere) = (3cm)^2 / (5cm)^2 = 9 / 25
Answer: 9 / 25
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area = ( top rule + bottom rule ) × height / 2
area = ( 2 + 3 ) × 4 / 2
area = 5 × 4 / 2
area = 20 / 2
area = 10
Negative 5 squared is negative 25
22 boxes still need to be given out
Answer:
Value is 15 and measure is 151