The molecular formula is D. C_8H_20O_4Si.
<em>Step 1</em>.Calculate the <em>empirical formula
</em>
a) Calculate the moles of each element
Moles of C= 196.01 g C × (1 mol C/12.01 g C) = 16.325 mol C
Moles of H = 41.14 g H × (1 mol H/1.008 g H) = 40.813 mol H
Moles of O = 130.56 g O × (1 mol O/16.00 g O) = 8.1650 mol O
Moles of Si = 57.29 g Si × (1 mol Si/28.085 g Si) = 2.0399 mol Si
b) Calculate the molar ratio of each element
Divide each number by the smallest number of moles and round off to an integer
C:H:O:Si = 8.0027:20.008:4.0027:1 ≈ 8:20:4:1
c) Write the empirical formula
EF = C_8H_20O_4Si
<em>Step </em>2. Calculate the <em>molecular formula</em>
EF Mass = 208.33 u
MF mass = 208.329 u
MF = (EF)_n
n = MF Mass/EF Mass = 208.329 u/208.33 u = 1.0000 ≈ 1
MF = C_8H_20O_4Si
Answer:
Mass of solvent is 1127.3 g
Explanation:
NaOCl → 3.62%
This percent means, that in 100 g of bleach solution, there are 3.62 g of NaOCl. So let's make a rule of three:
100 g of bleach solution have 3.62 g
1169.6 g of bleach solution may have (1169.6 . 3.62) /100 = 42.3 g
42.3 g is the mass of NaOCl in the solution
Mass of solution = Mass of solvent + Mass of solute
1169.6 g = Mass of solvent + 42.3 g
1169.6 g - 42.3 g = Mass of solvent → 1127.3 g
Molarity of a solution if 124.86 g of rbf are dissolved into a solution of water that has a final volume of 2.00L is 0.59.
<h3>What is molarity?</h3>
Molarity is used for dilute aqueous solutions held at a constant temperature. In general, the difference between molarity and molality for aqueous solutions near room temperature is very small and it won't really matter whether you use a molar or molal concentration.
MOLARITY = no of moles of solute/volume of soln in litres
No of moles of rbf = 124.6/104.46
= 1.19
Volume of soln = 2
Molarity=1.19/2 = 0.59
Learn more about Molarity here: brainly.com/question/26756988
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Answer:
True
Explanation:
All the above statements buttress the fact that the larger molecule, the greater the magnitude of London forces between the molecules. Each of the statements above is a confirmation/explanation of this general rule.
Answer:
v = 46.5 m/s
Explanation:
Given data:
Mass of car = 1210 kg
Momentum of car = 56250 kg m/s
Velocity of car = ?
Solution:
Formula:
p = mv
p = momentum
m = mass
v = velocity
Now we will put values in formula:
56250 kg m/s = 1210 kg × v
v = 56250 kg m/s / 1210 kg
v = 46.5 m/s
So a car having mass of 1210 kg with momentum 56250 kg m/s having 46.5 m/s velocity.