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denis23 [38]
2 years ago
6

What is the correct prefix for 6? O A. Oct- O B. Hepta- O C. Nano- O D. Hexa-

Chemistry
2 answers:
Zarrin [17]2 years ago
8 0
D should be correct
Alchen [17]2 years ago
4 0

Answer:

Hexa

Explanation:

Enjoy !

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Starting with a vessel of temperature 50.1°C, a pressure of 6263.MmHg and volume 461.1mL, what is its final volume, in liters, i
il63 [147K]

Answer:

The value of final volume inside the vessel  V_{2} =  5.17 ml

Explanation:

Initial pressure P_{1} = 6263 mm Hg = 8.24 atm = 835 K pa

Initial temperature T_{1} = 50.1 ° c = 323.1 K

Initial volume V_{1} = 461.1 ml =  0.0004611 m^{3}

Final temperature T_{2} = - 95.8 ° c = 177.2 K

Finial pressure P_{2} = 411 atm = 41644.6 K PA

We know that

P_{1} \frac{V_{1} }{T_{1} }  = P_{2} \frac{V_{2} }{T_{2} }

Put all the values in the above equation

⇒ 835 × \frac{0.0004611}{323.1} = 41644.6 × \frac{V_{2} }{177.2}

⇒ V_{2} = 5.07 × 10^{-6} m^{3}

⇒ V_{2} =  5.17 ml

This is the value of final volume inside the vessel.

8 0
3 years ago
Newton's Third Law: "For every action, there is an equal and opposite reaction." ... The forces are the result of
Whitepunk [10]

Answer:

The answer to your question is simultaneous. Hope it helps!

8 0
3 years ago
What happens in the artificial transmutation of an element? Include an example.
Mice21 [21]
What happens in the artificial transmutation is that the nucleous is bombarded with high energy particles which we can describe as kinetic energy and the idea for them is to induce what we call transmutation. Also what happens is that the high energy particles are accelerated. One of the examples is when nitrogen is transformed into hydrogen by combining its nucleous with an alpha particle
6 0
3 years ago
What is the theoretical yield of vanadium, in moles, that can be produced by the reaction of 1.0 mole of V2O5 with 4.0 moles of
IRINA_888 [86]

Answer:

Theoretical yield of vanadium = 1.6 moles

Explanation:

Moles of V_2O_5 = 1.0 moles

Moles of Ca = 4.0 moles

According to the given reaction:-

V_2O_5_{(s)} + 5Ca_{(l)}\rightarrow 2V_{(l)} + 5CaO_{(s)}

1 mole of V_2O_5 react with 5 moles of Ca

Moles of Ca available = 4.0 moles

Limiting reagent is the one which is present in small amount. Thus, Ca is limiting reagent. (4.0 < 5)

The formation of the product is governed by the limiting reagent. So,

5 moles of Ca on reaction forms 2 moles of V

1 mole of Ca on reaction for 2/5 mole of V

4.0 mole of Ca on reaction for \frac{2}{5}\times 4 mole of V

Moles of V = 1.6 moles

<u>Theoretical yield of vanadium = 1.6 moles</u>

4 0
3 years ago
Which is a mixture?
Rama09 [41]
Potassium and chlorine
5 0
3 years ago
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