Question

Find the value of x in each case. Please help me!!!!

Answer 1

M < JHG = 180 - 156 = 24 degrees
m < HGF = 24 degrees also ( alternate angles)
By external angle of a triangle theorem:-
2x = x + 24
x = 24   (answer)

Answer 2

$m\angle GHJ=180^o-156^o=24^o\\\\m\angle EFH=m\angle FHJ\\\\therefore\\\\2x=x+24^o\ \ \ |-x\\\\\boxed{x=24^o}$