Answer:
Step-by-step explanation:
hello,
I understand that there are only 4 cards and then the player draw a card out of the 4 cards, replace it so the second draw is still out of the 4 cards
<u>How many ways can you draw two cards?</u>
as the first card is replaced, this is 4*4=16
so there is 16 possibles ways
hearts hearts
hearts clubs
hearts diamonds
hearts spades
clubs hearts
clubs clubs
clubs diamonds
clubs spades
diamonds hearts
diamonds clubs
diamonds diamonds
diamonds spades
spades hearts
spades clubs
spades diamonds
spades spades
<u>out of these 16 ways, how many have same colour for both cards?</u>
I assume that there are only two colours Red and Black, so we can have
only 8 ways so the first probability is 8/16 = 1/2
<u>out of these 16 ways, how many are red ace first and black ace?</u>
There are 4 ways so the probability is 4/16 = 1/4
hope this helps
I think it is B. and the amount that they each need to pay is $1.13
Answer:he would have paid $6,968.00
Step-by-step explanation:
5200x0.085=442. 42/12=4. 4x422=1768
1768+5200=6968
Answer:
True
Step-by-step explanation:
So it is really easy to solve firstly we can see how much does the first 10 boxes make which makes around 55$ obviously. Secondly 45$ for the next 10 boxes.
So for now we can simply calculate that we have spent around 100$ which means 20 boxes. The remaining money left is 77$ so we can buy 77/3.5 = 22 only 22 boxes with that money. Hence a total of 42 boxes.
