A lizard is at the bottom of a 12 -foot well. each day it crawls up 5 feet, but each night it slips back 4 feet . after how ma
ny days will the lizard reach the top of the well?
1 answer:
12 feet
D1: 5 - 4 = 1 foot
D2: 1 + 5 = 6
6 - 4 = 2 ft
D3: 2 + 5 = 7
7 - 4 = 3 ft
D4: 3 + 5 = 8
8 - 4 = 4 ft
D5: 4 + 5 = 9
9 - 4 = 5 ft
D6: 5 + 5 = 10
10 - 4 = 6 ft
Each day the lizard moves up 1 foot. If you double the day it moved up 6 feet then you will get the day it moved up 12 feet.
D6 × 2 = D12
It will take the lizard 12 days to reach the top of the well.
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