Answer:
- (27n^3 - 12n - 1) over 3n
Step-by-step explanation:
Step-by-step explanation:
A pint has 2 cups
2 cups = 1 pint
1 cup = 1/2 pint
1/4 cup = 1/2 ÷ 4 = 1/2 * 1/4 = 1/8 pint
The number of possible combinations is given by
... C(18, 3) = 18!/(3!(18-3)!) = 18·17·16/(3·2·1) = 816 . . . . possible combinations
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There are 18 ways to choose the first one; 17 ways to choose the second one, and 16 ways to choose the 3rd one. The same 3 students can be chosen in any of 3! = 6 different orders, so the product 18·17·16 must be divided by 6 to get the number of possible combinations in which order doesn't matter.
The Multiplication Property of Zero.
It states "the product of any number and zero is zero". Even if there are more than one multiplier - it is still 0.
So 5 x 0 = 0
100 x 0 = 0
41 x 0 x 3 = 0
etc.
the second one, and the third one
