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2 years ago

13

Put in Standard form: y – 4 = 3(x+5)

2 answers:

Sophie [7]2 years ago

8 0

Answer:

3x - y= - 19

Step-by-step explanation:

Zarrin [17]2 years ago

8 0

Answer:

y-4=3x+15

y=3x+15+4

y=3x+19

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The width of the figure below is 5 units. The perimeter of the figure is 18 units. What is the length of the figure in units?

Talja [164]

The perimeter is all sides length added together. You can make an equation:5+5+x+x where x is the length.
5+5=10 18-10=8 There is two sides so you do eight divided by two
The length is 4

4 0

3 years ago

Read 2 more answers

If 5 + 20 times 2 Superscript 2 minus 3 x Baseline = 10 times 2 Superscript negative 2 x Baseline + 5, what is the value of x? –

sp2606 [1]

Answer:

<h3>Option D) 3 is correct</h3><h3>Therefore the value of x is 3</h3>

Step-by-step explanation:

Given equation is $5+20\times (2)^{2-3x}=10\times (2)^{-2x}+5$

<h3>To find the value of x :</h3>

First solving the given equation we have,

$5+20\times (2)^{2-3x}=10\times (2)^{-2x}+5$

$5+20\times (2)^{2-3x}-5=10\times (2)^{-2x}+5-5$

$20\times (2)^{2-3x}=10\times (2)^{-2x}$

$20\times (2)^2.(2)^{-3x}=10\times (2)^{-2x}$

$20\times 4.(2)^{-3x}=10\times (2)^{-2x}$

$80(2)^{-3x}=10\times (2)^{-2x}$

$\frac{80}{10}(2)^{-3x}=\frac{10\times (2)^{-2x}}{10}$

$8(2)^{-3x}=(2)^{-2x}$

$\frac{(2)^{-3x}}{(2)^{-2x}}=\frac{1}{8}$

$(2)^{-3x}.(2)^{2x}=\frac{1}{2^3}$ ( by using the property $\frac{1}{a^{-m}}=a^m$ )

$2^{-3x+2x}=\frac{1}{2^3}$ ( by using the property $a^m.a^n=a^{m+n}$ )

$2^{-x}=\frac{1}{2^3}$

$\frac{1}{2^x}=\frac{1}{2^3}$ ( by using the property $a^{-m}=\frac{1}{a^m}$ )

Since bases are same so powers are same

Therefore we can equate the powers we get x=3

<h3>Therefore the value of x is 3</h3><h3>Option D) 3 is correct</h3>

5 0

3 years ago

Read 2 more answers

What’s 18 divided by 7?

GalinKa [24]

Here is the answer...

2.57142857143

7 0

3 years ago

Angie goes to a fair that charges $8 admission and $0.75 per ride.

faltersainse [42]

0.75 x 5 because she has already rode 1 and then subtract it from 8.00$ and that should give you the answer

5 0

3 years ago

Jared bought a Suzuki 1000 for $12,698. If it depreciates at a rate of 11% per year, how much will it be worth in 3 years

Serga [27]

Original price = P = $12,698
Depreciation rate = r = 11% = 0.11
Time in years = t = 3
New price = A

The formula used will be:

$A=P(1-r)^{t}$

Using the values, we get:

$A=12698(1-0.11)^{3}=8951.70$

Thus, the worth of Suzuki after 3 years will be $8951.70

7 0

2 years ago