y = 0.6x - 3.2
The general form of the desired equation is
y = mx + b
where
m = slope of the line
b = y intercept of the line
If two lines are parallel, their slopes will be the same, Since the slope of the
given line "y = 0.6x +3" is 0.6, that will also be the slope of the desired line.
So our equation becomes:
y = 0.6x + b
Now we can substitute the x and y value of the desired point we want the new line to pass through and find b. So
y = 0.6x + b
-5 = 0.6(-3) + b
-5 = -1.8 + b
-3.2 = b
So the desired equation is now
y = 0.6x - 3.2
Am going to presume you want it solved.
Please pardon my presumption
7 - (2/3)x < x - 8, Take all the x to one side of the inequality
-(2/3)x-x < - 8 -7
-(5/3)x < - 15 Divide both sides by -5/3 and inequality sign changes
x > (-15)/(-5/3)
x > 15 * 3/5 . 5 into 15 is 3.
x > 3*3
x > 9
You need to expand the brackets eg.
(w-9)8 basically means 8 x (w-9) = 8w-72
(4,9) is in quarter I and (4,-9) is in quarter IV of the graph. (4,-9) is the point (4,9) reflected over the x-axis. they are similar bc both have 4 as their x coordinate.
