The initial velocity of the fish is the same as that of the pelican and it is -0.50 m/s. The distance traveled by the object is given by the equation, d = (V1)t + 0.5at² where t is equal to 2.50s and the acceleration due to gravity, a, is 9.80 m/s². Substituting, d = (-0.50 m/s)(2.5 s) + 0.5(9.8 m/s²)(2.50 s)² d = 30.625 m Thus, the answer is letter C.
