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basically you treat y like a number and not a variable
Answer:
a is 4
b is 2y
c is -10y²+9
discriminant is 4(41y²-36)
Step-by-step explanation:
4x²+2xy-10y²+9=0
rewrite in standard form of a quadratic equation like ax² + bx + c = 0
4x²+2yx-10y²+9=0
basically you treat y like a number and not a variable
a is the number with the x²
right away we know a is 4 because of 4x²
b is the one with x so in this formula b is 2y
c is the number without the x which in this case is -10y²+9
discriminant is
b² - 4ac
(2y)²- (4)(4)(-10y²+9)
4y²-(16)(-10y²+9)
4y²-(16)(-10y²+9)
4y²+160y²-144
164y²-144 =
4(41y²-36)
Answer:
Step-by-step explanation:
Given:
m∠1 = 65°
Since. ∠1 and ∠2 are the angles of linear pair,
m∠1 + m∠2 = 180°
65° + m∠2 = 180°
m∠2 = 115°
m∠1 = m∠3 [Vertical angles]
m∠3 = 115°
Since, ∠1 and ∠4 is the linear pair of angles,
m∠1 + m∠4 = 180°
65° + m∠4 = 180°
m∠4 = 180 - 65 = 115°
m∠4 + m∠5 = 180° [Consecutive interior angles between the parallel lines]
115° + m∠5 = 180°
m∠5 = 180° - 115° = 65°
m∠5 + m∠6 = 180° [Linear pair of angles]
65° + m∠6 = 180°
m∠6 = 115°
m∠5 = m∠7 [Vertical angles]
m∠5 = m∠7 = 65°
m∠6 = m∠8 [Vertical angles]
m∠6 = m∠8 = 115°