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3 years ago

When will diffusion slow down

Chemistry

1 answer:

scZoUnD [109]3 years ago

6 0

Answer:

Exchange across cell membranes - diffusion. The higher the concentration gradient, the faster the rate of facilitated diffusion, up to a point. As equilibrium is reached the concentration gradient is much lower because the difference in concentrations is very small so the rate of facilitated diffusion will slow down and level off.

Explanation:

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The row or period on the periodic table tells us

ololo11 [35]

Answer:

its a

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2 years ago

Hydrochloric acid reacts with calcium to form hydrogen and calcium chloride. if 100 grams of hydrochloric acid reacts with 100 g

natita [175]

The balanced chemical reaction is:

2HCl + Ca = CaCl2 + H2

We are given the amount of the reactants to be used for the reaction. These values will be the starting point of our calculations.

100 g HCl ( 1 mol HCl / 36.46 g HCl ) = 2.74 mol HCl

100 g Ca ( 1 mol Ca / 40.08 g ) = 2.08 mol Ca

From the reaction, the mole ratio of the reactants is 2:1 where every 2 moles of hydrochloric acid, 1 mole of calcium is required. Therefore, the limiting reactant for this case is calcium.

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3 years ago

Read 2 more answers

For the imine synthesis reaction, the two reactants react in melting state. How is that possible since the melting points for bo

pychu [463]

Answer:

I have no clue at all im in 11 and dont know anything lol byeeee

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3 years ago

Which one of the following compounds produces a basic solution when

JulsSmile [24]

Answer:

Rb2O

Explanation:

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2 years ago

at a particulat temperature, a smaple of pure water has a Kw of 7.7x10-14. what is the hydroxide concentration of this sample

ycow [4]

Answer: The hydroxide concentration of this sample is $3.85\times 10^{-7}$

Explanation:

When an expression is formed by taking the product of concentration of ions raised to the power of their stoichiometric coefficients in the solution of a salt is known as ionic product.

The ionic product for water is written as:

$K_w=[H^+]\times [OH^-]$

$7.7\times 10^{-14}=[H^+]\times [OH^-]$

As $[H^+]=[OH^-]$

$2[OH^-]=7.7\times 10^{-14}$

$[OH^-]=3.85\times 10^{-7}$

Thus hydroxide concentration of this sample is $3.85\times 10^{-7}$

4 0

2 years ago