Answer:
74.0 g/mol
Explanation:
Step 1: Write the generic neutralization reaction
HA + NaOH ⇒ NaA + H₂O
Step 2: Calculate the reacting moles of NaOH
At the equivalence point, 33.83 mL of 0.115 M NaOH react.
0.03383 L × 0.115 mol/L = 3.89 × 10⁻³ mol
Step 3: Calculate the moles of HA that completely react with 3.89 × 10⁻³ moles of NaOH
The molar ratio of HA to NaOH is 1:1. The reacting moles of HA is 1/1 × 3.89 × 10⁻³ mol = 3.89 × 10⁻³ mol.
Step 4: Calculate the molar mass of the acid
3.89 × 10⁻³ moles of HA have a mass of 0.288 g.
M = 0.288 g / 3.89 × 10⁻³ mol = 74.0 g/mol
Answer:
<u>Models are limited by science - the more that was discovered, the better the model could be made.</u>
Explanation:
Models in science are meant to represent things in science. Since science controls the reliability of a model, when science changes, so does the model. Otherwise the model would be pseudoscientific.
Well i do think they're the same.
5.00 moles of a binary, group 2 oxide are found to have a mass of 521 g. The group 2 metal is Strontium.
According to question 5 moles of binary group 2 metal oxide mass =521 g
So, 1-mole metal oxide mass will be =521 / 5=104.2 g
Now, as metal oxide is group 2 oxide so metal: oxygen =1: 1
So the mass of metal is =104.2-16=88.2 gm (as the atomic mass of oxygen is 16 g
Therefore, the metal is Strontium(Sr) whose atomic mass is 87.62 g which is nearly 88.2 gm
So, the formula of metal oxide is SrO
The group two metal here is Sr which is strontium and lies in the same group as calcium.
To learn more about group 2 metals, visit:
brainly.com/question/18328178
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