Question

How many milliliters of a 0.275 M NaOH solution is required to react with 0.450 L of CO2 gas

Answer 1

Volume of NaOH required to react = 145.5 ml

Further explanation

Reaction

CO₂(g) + 2 NaOH(aq)  ⇒Na₂CO₃(aq) + H₂O(l)

The volume of CO₂ : 0.45 L

mol CO₂ at STP (O C, 1 atm) ⇒ at STP 1 mol gas 22.4 L :

$\tt mol~CO_2=\dfrac{0.45}{22.4}=0.02$

From the equation, the mol ratio of CO₂ : NaOH = 1 : 2, so mol NaOH :

$\tt mol~NaOH=\dfrac{2}{1}\times 0.02=0.04$

Then volume of NaOH :

$\tt V=\dfrac{n}{M}\\\\V=\dfrac{0.04}{0.275}\\\\V=0.1455~L\rightarrow 145.5~mL$