Make slope intercept
3x - y = 5
3x = y + 5
y = 3x - 5
Parallel = same slope
Slope = 3
Y = 3x + b
Plug in the point
-2 = 3(-1) + b
-2 = -3 + b, b = 1
Solution: y = 3x + 1
5 x 1 = 5
5 x 2 = 10
5 x 3 = 15
5 x 7 = 35
Answer:
It is either A or B. I am not certain only because I do not know if your assignement is indicating that the underlined greater sign represents an open dot or a closed dot
All we need is to put this form in the vertex form f(x) = (ax+b)^2 + c
So we have <span>f (x)= 3x^2+12x+11 ....
Let's complete the square (if you aware of it)
</span><span>
f(x)= 3x^2+12x+11 = 3(x^2+4x)+11 = 3(x^2+4x+4-4)+11
=</span><span> 3([x^2+4x+4]-4)+11 = 3[(x+2)^2-4]+11 =3</span><span>(x+2)^2 - 12 +11 = 3</span><span><span>(x+2)^2 -1
so our form would be:

Here is a parabola with vertex of (-2,-1) and with positive </span> slope (concave up)
</span>
I hope that
helps!
10^4 = 10,000
9 x 10,000 = 90,000