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Alex17521 [72]
3 years ago
11

Find the least common multiple of 16 , 21, and 24

Mathematics
1 answer:
sdas [7]3 years ago
8 0

336 is the LCM for above group of non-negative integers and is divisible by each integers of this group.

Problem & Workout :

step 1 Address input parameters & values.

16 21 24

lcm (16, 21, 24) = ?

step 2 Arrange the group of numbers in the horizontal form with space or comma separated format

16, 21 and 24

step 3 Choose the divisor which divides each or most of the integers of in the group (16, 21 and 24), divide each integers separately and write down the quotient in the next line right under the respective integers. Bring down the integer to the next line if the integer is not divisible by the divisor. Repeat the same process until all the integers are brought to 1.

LCM of 16, 21 and 24

16 21 24

2 21 3

2 7 1

1 7 1

1 1

step 4 Multiply the divisors to find the lcm of 16, 21 and 24

8 x 3 x 2 x 7 = 336

lcm (16, 21, 24) = 336

336 is least common multiple for three numbers 16, 21 and 2

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andre [41]

Answer:

a= 32 degrees

b= 148 degrees

c= 82 degrees

6 0
3 years ago
Two ways to solve 2(4x-11)=10
Leokris [45]
Hi there,

2 (4x - 11) = 10
4x - 11 = 5
4x = 5 + 11
4x = 16 then divide both sides by 4
16 divided by 4 = 4

Hope this helps :)
3 0
3 years ago
A certain plant runs three shifts per day. Of all the items produced by the plant, 50% of them are produced on the first shift,
Snezhnost [94]

Answer:

0.2941 = 29.41% probability that it was manufactured during the first shift.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Defective

Event B: Manufactured during the first shift.

Probability of a defective item:

1% of 50%(first shift)

2% of 30%(second shift)

3% of 20%(third shift).

So

P(A) = 0.01*0.5 + 0.02*0.3 + 0.03*0.2 = 0.017

Probability of a defective item being produced on the first shift:

1% of 50%. So

P(A \cap B) = 0.01*0.5 = 0.005

What is the probability that it was manufactured during the first shift?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.005}{0.017} = 0.2941

0.2941 = 29.41% probability that it was manufactured during the first shift.

6 0
3 years ago
HELP any1 good at math?
valentina_108 [34]

Step-by-step explanation:

the equations are :-

=》d = 40m + 200

=》d = 50m

here, by equalising both equations.

( since, d = d )

=》40m + 200 = 50m

=》50m - 40m = 200

=》10m = 200

=》m = 200 ÷ 10

=》m = 20

now,

=》d = 50m

=》d = 50 × 20

=》d = 1000

6 0
3 years ago
A home with an area of 2,200 square feet has 660 square feet of wood flooring. What percent of the home's flooring is wood
zheka24 [161]

Answer:

30%

Step-by-step explanation:

Given data

Area of Home= 2,200 square feet

Area of wood flooring=  660 square feet

The percent of wood flooring in the house can be gotten as

=660/2200*100

=0.3*100

= 30%

Hence the wooden floor occupies 30%.

7 0
3 years ago
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