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lisov135 [29]
4 years ago
5

Car A has twice the mass of car B , and car A has the half the kinetic energy of car B . How do their speeds compare?

Physics
1 answer:
Llana [10]4 years ago
8 0

Answer:

Speed of car A is half the speed of car B.

Explanation:

Kinetic energy, KE=\frac{1}{2}mv^2

Car A has twice the mass of car B.

         m_A=2m_B

Car A has the half the kinetic energy of car B

         KE_A=\frac{1}{2}KE_B

We have

          KE_A=\frac{1}{2}KE_B\\\\\frac{1}{2}m_Av_A^2=\frac{1}{2}\times \frac{1}{2}m_Bv_B^2\\\\\frac{1}{2}\times 2m_Bv_A^2=\frac{1}{2}\times \frac{1}{2}m_Bv_B^2\\\\v_A^2=\frac{v_B^2}{4}\\\\v_A=\frac{v_B}{2}

Speed of car A is half the speed of car B.

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Answer:

For object A

m = 5 kg ,   v= -11 j

For B object

m = 6 kg  ,  v= 5 i +8.7 j

For object C

m = 10 kg   ,   v= -10 i

We know that

Linear momentum   P= m v   kg.m/s

a) A and C

Momentum in y direction

Py=- 5 x 11 j= - 55 j  kg.m/s

Momentum in x direction

Px=- 10 x 10 j= - 100 i    kg.m/s

b) B and C

Momentum in y direction

Py=6 x 8.7 j= 52.2 j    kg.m/s

Momentum in x direction

Px=( 6 x 5 - 10 x 10 ) i = - 70 i   kg.m/s

c) A ,B and C

By using data of a and b

Momentum in y direction

Py= 6 x 8.7 - 5 x 11 j= -2.8 j    kg.m/s

Momentum in x direction

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4 0
3 years ago
A ruler vibrates 70 times in 20 seconds.what is the frequency of its vibration
Bad White [126]

Answer:

we know that that frequency= n/t

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Explanation:

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8 0
3 years ago
a coin is dropped from the top of a tall building. determine the coin's (a) velocity and (b) displacement after 1.5 sec.
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3 0
4 years ago
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A light spring of constant 179 N/m rests vertically on the bottom of a large beaker of water. A 5.32 kg block of wood of density
Digiron [165]

Answer:

Compression of the spring: 0.18 m (downward)

Explanation:

The forces acting on the block of wood are:

- The force of gravity, acting downward, of magnitude mg, where m = 5.32 kg is the mass of the block and g=9.8 m/s^2 is the acceleration due to gravity

- The force exerted by the spring, downward, of magnitude kx, where k=179N/m is the spring constant and x is the elongation of the spring

- The buoyant force, upward, of magnitude \rho V g, where \rho=1000 kg/m^3 is the water density and V the volume of the block

Since the block is in equilibrium, the net force is zero, so we can write

mg+kx-\rho V g=0 (1)

We have to find the volume of the block first. We have:

m = 5.32 kg (mass)

\rho_w = 622 kg/m^3 (wood density)

So, the volume is

V=\frac{m}{\rho_w}=\frac{5.32}{622}=0.0086 m^3

So now we can re-arrange eq.(1) to find the elongation of the spring, x:

x=\frac{-mg+\rho Vg}{k}=\frac{-(5.32)(9.8)+(1000)(0.0086)(9.8)}{179}=0.18 m

So, the spring is compressed by 0.18 m.

7 0
3 years ago
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