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lyudmila [28]
3 years ago
13

An accelerometer is a device that uses the extension of a spring to measure acceleration in terms of Earth's gravitational accel

eration (g). What is the approximate acceleration if this accelerometer spring is extended just 0.43 centimeters?. . a) 0.24 g. b) 0.80 g. c) 2.00 g. d) 2.40 g
Physics
2 answers:
Nimfa-mama [501]3 years ago
8 0

0.80g (B) is correct for plato!

ELEN [110]3 years ago
3 0
In your question explains that an accelerometer is a device that uses the extension spring to measure acceleration in terms of Earth's Gravitational accelerations. So if this device is extended just 0.43 centimeters the possible accelerations is letter B. 0.80 g
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Astronomers have found water on mars.
vodomira [7]

The thin atmosphere of Mars is thought to be due to the planet's lack of a magnetic field, which has allowed the Solar wind to blow away much of the gas the planet once had. Venus, despite still having a thick atmosphere of CO2, surprisingly has a similar problem

4 0
1 year ago
Four particles are in a 2-d plane with masses, x- and y- positions, and x- and y- velocities as given in the table below: what i
Arte-miy333 [17]
I attached the picture of the missing table.
Center of mass is the point such that if you apply force to it, the system would move without rotating.
We can use following formula to calculate the center of mass:
R=\frac{1}{M}\sum_{i=1}^{n=i}m_ir_i
Where M is the sum of the masses of all particles.
Part 1
To calculate the x coordinate of the center of mass we will use this formula:
R_x=\frac{1}{M}\sum_{i=1}^{n=i}m_ix_i
I will do all the calculations in the google sheet that I will share with you.
For the x coordinate of the center of mass we get:
R_x=0.96m
Part 2
To calculate the y coordinate of the center of mass we will use this formula:
R_y=\frac{1}{M}\sum_{i=1}^{n=i}m_iy_i
I will do all the calculations in the google sheet that I will share with you.
For the x coordinate of the center of mass we get:
R_y=-0.84m
Part 3
We will calculate speed along x and y-axis separately and then will add them together.
v_x=\frac{\sum_{i=1}^{n=i}m_iv_x_i}{M}
v_y=\frac{\sum_{i=1}^{n=i}m_iv_y_i}{M}
Total velocity is:
v=\sqrt{v_x^2+v_y^2}
Once we calculate velocities we get:
v_x=-1.08\frac{m}{s}\\ v_y=-0.03\frac{m}{s}\\ v=\sqrt{(-1.08)^2+(-0.03)^2}=1.08\frac{m}{s}
Part 4
Because origin is left to our center of mass(please see the attached picture) placing fifth mass in the origin would move the center of mass to the left along the x-axis.
Part 5
If you place fifth mass in the center of the mass nothing would change. The center of mass would stay in the same place.
Here is the link to the spreadsheet:
https://docs.google.com/spreadsheets/d/1SkQHbI1BxiJnwpWbLmP0XWgcNPrGquH1K2MfN6cznVo/edit?usp=sharing

3 0
2 years ago
Amy has a mass of 30 kg, and she is riding a skateboard traveling 5 m/s. What is her momentum?
Flauer [41]
Hey there!

So we know that m*v=P.
And in this question m=30
v=5 m/s
P = 30*5 Kgm/s
P = 150 Kgm/s

So, your final answer is 150 Kg.m/s

Hope this helps! :)
5 0
3 years ago
Read 2 more answers
What is the average de Broglie wavelength of oxygen molecules in air at a temperature of 27°C? Use the results of the kinetic th
asambeis [7]

Answer:

\lambda = 2.57 \times 10^{-11} m

Explanation:

Average velocity of oxygen molecule at given temperature is

v_{rms} = \sqrt{\frac{3RT}{M}}

now we have

M = 32 g/mol = 0.032 kg/mol

T = 27 degree C = 300 K

now we have

v_{rms} = \sqrt{\frac{3(8.31)(300)}{0.032}

v_{rms} = 483.4 m/s

now for de Broglie wavelength we know that

\lambda = \frac{h}{mv}

\lambda = \frac{6.6 \times 10^{-34}}{(5.31\times 10^{-26})(483.4)}

\lambda = 2.57 \times 10^{-11} m

7 0
3 years ago
How fast must a 1000 kg car be moving to have a kinetic energy of 2.0*10^3
lawyer [7]
Kinetic Energy is defined by Ke=1/2mv^2. Plug in and solve for v.

2,000 = 1/2(1000)(v)^2
4=(v)^2
v=2 m/s

The car must move at 2 m/s to have a Ke of 2,000 Joules.
6 0
2 years ago
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