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lyudmila [28]
4 years ago
13

An accelerometer is a device that uses the extension of a spring to measure acceleration in terms of Earth's gravitational accel

eration (g). What is the approximate acceleration if this accelerometer spring is extended just 0.43 centimeters?. . a) 0.24 g. b) 0.80 g. c) 2.00 g. d) 2.40 g
Physics
2 answers:
Nimfa-mama [501]4 years ago
8 0

0.80g (B) is correct for plato!

ELEN [110]4 years ago
3 0
In your question explains that an accelerometer is a device that uses the extension spring to measure acceleration in terms of Earth's Gravitational accelerations. So if this device is extended just 0.43 centimeters the possible accelerations is letter B. 0.80 g
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A bulldozer attempts to drag a log weighing 500 N along the rough horizontal ground. The cable attached to the log makes an angl
Gemiola [76]

Answer:

T= 224.01 N

Explanation:

in imminent motion we have to :

  • The frictional force reaches its maximum value
  • The system is in balance of forces

Data

W=  500 N :  weight of the log

μs = 0.5

μk = 0.35

α = 30°above the ground :  angle of the cable attached to the log

Newton's first law to the log:

∑F =0 Formula (1)

∑F : algebraic sum of the forces in Newton (N)

Forces acting on the log

T: cable tension for impending movement

N: normal force

W : weight

f: frictional force , f= μsN

We apply the formula (1)

∑Fx=0

Tx-f = 0

Tcosα-μsN=0

Tcos30°-0.5N=0 Equation (1)

∑Fy=0

N+Ty-W=0

N+Tsin30°-500=0

N= 500-Tsin30°  Equation (2)

We replace the value of N of the Equation  (2) in the equation (1)

Tcos30°-0.5(500-Tsin30°) = 0

Tcos30°+0.5Tsin30° = 0.5*500

T( cos30°+0.5*sin30°) = 250

(1.116) T = 250

T= 250/1.116

T= 224.01 N

6 0
3 years ago
A 0.0780 kg lemming runs off a 5.36 m high cliff at 4.84 m/s. what is its potential energy (PE) when it is 2.00 m above the grou
IceJOKER [234]

The potential energy is 4.10 J

Explanation:

The potential energy of a body is given by

U=mgh

where

m is the mass of the object

g is the acceleration of gravity

h is the height of the object relative to the ground

For the lemming in this problem we have

m = 0.078 kg is its mass

h = 5.36 m is the height above the ground

g=9.8 m/s^2 is the acceleration of gravity

Solving the equation,

U=(0.078)(9.8)(5.36)=4.10 J

Learn more about potential energy here:

brainly.com/question/1198647

brainly.com/question/10770261

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7 0
4 years ago
Calculate the net convective heat transfer loss rate from both vertical surfaces of the plate to the air. (hint: h values should
pychu [463]

Net convective heat transfer loss rate (gnet)

Gnet = 2h, A (Ts - T∞)

=2(4.51) (0.001) (25)

Gnet = 0.2250 W.

There are two types of convection: natural convection and forced convection. Natural convection is caused by differences in the density of liquids due to differences in temperature (eg "hot air rises"). Global atmospheric circulation and local weather phenomena (including wind) are due to convective heat transfer.

Newton's Law of Cooling is a widely used equation for calculating both forced and natural net convective. The formula for Newton's Law of Cooling is Q = h A ΔT. Equation parameters and their typical US and SI.

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7 0
2 years ago
If the mass of a pendulum is increased (with other factors controller), would the period (time) decrease or stay the same?
Akimi4 [234]
The period of the pendulum depends only on the length from the pivot to the "center of mass". So if the string has no mass, then the amount of mass on the end doesn't make any difference.
But if the pendulum is suspended on, say, a chain with mass, then the more mass on the bottom, the lower the center of mass is, and the longer the period is.
8 0
4 years ago
Ple can someone help me to answer this question
ra1l [238]

The length of the uniform meter stick is 50 cm and the mass of the uniform meter stick is 50 g.

<h3 /><h3>A sketch of the uniform stick and the mass</h3>

The sketch of the uniform stick and the mass will be two based on the given statement.

<h3>when the uniform stick balances on knife at 10 cm from one end;</h3>

-------------------------------------------------------  

↓      10cm           Δ       (L - 10 cm)         ↓

200g                                                      M

<h3>When the knife edge is moved 5 cm further</h3>

|---------------15 cm-----------------|

-----------------------------------------------------------------------

              ↓      8.75 cm           Δ       (L - 15 cm)         ↓

          200g                                                               M

From the first diagram, apply principle of moment;

200(10) = M(L - 10) ------- (1)

From the second diagram, apply principle of moment;

200(8.75) = M(L - 15)   ------- (2)

From equation (1); M = (2000) / (L - 10)

From equation (2); M = (1750) / (L - 15)

Solve (1) and (2);

(2000) / (L - 10) = (1750) / (L - 15)

1750(L - 10) = 2000(L - 15)

L - 10 = 2000/1750(L - 15)

L - 10 = 1.143(L - 15)

L - 10 = 1.143L - 17.14

17.14 - 10 = 1.143L - L

7.14 = 0.143L

L = 7.14/0.143

L = 50 cm

<h3>Mass of the uniform stick</h3>

M = (2000) / (50 - 10)

M = 50 g

Thus, the length of the uniform meter stick is 50 cm and the mass of the uniform meter stick is 50 g.

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8 0
2 years ago
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