Question

The pressure observed after reaction with Zn metal and HCl should be corrected to subtract the pressure due to water vapor present at the final system temperature (22°C). Write down the corrected pressure P:________

Answer 1

Answer:

The correct answer to the following question will be "Pressure = 18394.168 torr".

Explanation:

The reaction is:

Zn + 2HCl ⇒ ZnCl2 + H2

Let,

H2 = 1 mole

Volume, V = 1 L

As we know,

$Pressure(P) = \frac{nRT}{V}$

On putting the values in the above formula, we get

$P=\frac{1\times 0.0821\times 295.15}{1}$

$P=24.2318 \ atm$

$P=24.2318\times 760$

$P=18416.168 \ torr$

Now,

$P \ original = P \ obtained-PH2O$

$P \ original=18416.168-22$

$P \ original=18394.168 \ torr$