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Shtirlitz [24]
2 years ago
13

A spiracle polish metallic ball is uses a diverging mirror with a focal length of -20 cm a bird 25 cm tall standing 50 cm away L

ooks directly at the mirror what are the size and position of the birds image
Physics
1 answer:
Aleksandr-060686 [28]2 years ago
5 0

Answer:

1/f = 1/i + 1/o      thin lens equation

1/i = 1/f - 1/o

i =  o * f / ( o - f) = 50 * (-20) / (50 - (-20)) = -14.3 cm

The final image is  erect and 14.3 cm behind the curved surface

M = -o / i = 14.3 / 50 = .29      magnificaton of object

S = .29 * 25 cm = 7.1 cm       appearance of bird in mirror (height)

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brainly an andean condor with a wingspan and a mass soars along a horizontal path. model its wings as a rectangle with a width.
Anna35 [415]

The difference between the pressure at the top surfaces of the condor's wings and the pressure at the bottom surfaces is 101,204 Pa.

<h3>Difference in pressure between the top and bottom of the wingspan</h3>

The difference in pressure between the top and bottom of the wingspan is calculated as follows;

ΔP = P(top) - P(bottom)

<h3>Area of the wingspan</h3>

A = bh

A = 2.7 m x 0.27 m

A = 0.729 m²

<h3>Weight of the Andean condor</h3>

W = mg

W = 9 x 9.8

W = 88.2 N

<h3>Pressure at the top surface of condor's wings</h3>

The pressure at the top surface of condor's wings is due to atmospheric pressure

P(top) = 14.7 Psi = 101,325 Pa

<h3>Pressure at the bottom surface of condor's wings</h3>

The pressure at the bottom surface is due to weight of andean condor.

P = W/A

P(bottom) = 88.2/0.729

P(bottom) = 120.99 Pa

The difference between the pressure at the top surfaces of the condor's wings and the pressure at the bottom surfaces is calculated as;

ΔP = P(top) - P(bottom)

ΔP = 101,325 Pa - 120.99 Pa

ΔP = 101,204 Pa

The complete question is below;

An Andean condor with a wingspan of 270 cm and a mass of 9.00 kg soars along a horizontal path. Model its wings as a rectangle with a width of 27.0 cm.

Learn more about pressure here: brainly.com/question/25736513

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2 years ago
The magnetic field at the equator points north. if you throw a positively charged object (for example, a baseball with some elec
asambeis [7]
Recall the equation for magnetic force:

F = qv x B          *x is cross product, not separate variable!

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Hope this helps!
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3 years ago
Suppose that a charged particle of diameter 1.00 micrometer moves with constant speed in an electric field of magnitude 1.00×105
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It's a bit of a trick question, had the same one on my homework. You're given an electric field strength (1*10^5 N/C for mine), a drag force (7.25*10^-11 N) and the critical info is that it's moving with constant velocity(the particle is in equilibrium/not accelerating). 
<span>All you need is F=(K*Q1*Q2)/r^2 </span>
<span>Just set F=the drag force and the electric field strength is (K*Q2)/r^2, plugging those values in gives you </span>
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3 years ago
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An open pipe of length 0.39 m vibrates in the third harmonic with a frequency of 1400 Hz what is the distance from the center of
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Length of the pipe = 0.39 m

Number of harmonics = 3

Now there are 3 loops so here we can say

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So distance between node and its nearest antinode will be

d = \frac{\lambda}{4}

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So the distance will be 6.5 cm

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3 years ago
Is Mars a gas planet or a rocky planet?
OLEGan [10]
Mars is a rocky planet
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2 years ago
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