Answer:
24 more chocolotae chip cookies are sold
Step-by-step explanation:
CCC 7(15)+6 105+6=111
SC 6(15)-3 90-3 = 87
111-87 = 24
Answer:

Step-by-step explanation:
Let's start by using change of base property:

So, for 

Now, using change of base for 

You can express
as:

Using reduction of power property:


Therefore:

As you can see the only difference between (1) and (2) is the coefficient
:
So:


Answer:
x = 3, line AB = 17 , and line CD = 17
y = 10, angle A = 70, and angle D = 70
Step-by-step explanation:
well since their the same length you can put them equal to each otheir
5x + 2 = 8x - 7
subtract 5x by both sides to get --> 2 = 3x -7
add 7 to both sides and get --> 9 = 3x
divide 3 by both sides to get x = 3
now plug it back in each equation we started with and get you answers
Same steps for y but different equations
The answer to the missing value is X = 3
Solving the equation
we get value of p = -4
Step-by-step explanation:
We need to find the value of p in the equation 
Solving to find value of p:

So, solving the equation
we get value of p = -4
Keywords: Solving Equations
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