Which of the following is an undefined term in geometry?

Addison earn $25 mowing her neighbor's lawn then she loaned her friend $18 and got 50 from her grandmother for her birthday she

yarga [219]

Solution: The total money did addison have to begin with is $29.

Explanation:

Let the addison begin with money $x.

It is given that the addison earn $25 from his neighbor and $50 from her grandmother. So total money addison has $\$x+\$25+\$50=\$x+\$75$

She loaned her friend %18.

Now she has $\$x+\$75-\$18=\$x+\$57$

It is given that she had $86.

$\$x+\$57=\$86\\\$x=\$86-\$57\\\$x=\$29$

Therefore, the total money did addison have to begin with is $29.

4 0

3 years ago

Read 2 more answers

Which expression is equivalent to (15aºb²c34) (3a166-29cº) for all values of a, b, and

hodyreva [135]

The answer is 45a16c34b27

6 0

2 years ago

What is 99.9999 rounded to the nearest hundredth

Yuki888 [10]

100 would be correct because the 9 in the hundredths place rounds to a ten, and so does every other number.

5 0

3 years ago

Read 2 more answers

Slices of pizza for a certain brand of pizza have a mass that is approximately normally distributed with a mean of 67.7 grams an

Alexxx [7]

Answer:

a. s.e. = 0.338

b. The probability of finding a random slice of pizza with a mass of less than 67.2 grams is 0.5871 or 58.71%

c. The probability of finding a 20 random slices of pizza with a mean mass of less than 67.2 grams is 0.0694 or 6.94%

d. The sample mean of 62.75 would represent the 15th percentile

Step-by-step explanation:

1. Let's review the information provided to us to answer the question properly:

μ of the mass of slices of pizza for a certain brand = 67.7 grams

σ of the mass of slices of pizza for a certain brand = 2.28 grams

2. For samples of size 20 pizza slices, what is the standard deviation for the sampling distribution of the sample mean?

Let's recall that the standard deviation of the sampling distribution of the mean is called the standard error of the mean and its formula is:

μσs.e.= √σ/n, where n is the sample size.

s.e. = √2.28/20

s.e. = 0.338

3. What is the probability of finding a random slice of pizza with a mass of less than 67.2 grams?

Let's find the z-score for X = 67.2, this way:

z-score = (X - μ)/σ

z-score = (67.2 - 67.7)/2.28

z-score = 0.5/2.28

z-score = 0.22 (rounding to the next hundredth)

Now, using the z-table, let's find p, the probability:

p (z = 0.22) = 0.5871

The probability of finding a random slice of pizza with a mass of less than 67.2 grams is 58.71%

4. What is the probability of finding a 20 random slices of pizza with a mean mass of less than 67.2 grams?

Let's use the central limit theorem to find the z-score, this way:

z-score = X - μ/s.e

z-score = 67.2 - 67.7/0.338

z-score = -0.5/0.338

z-score = - 1.48

Now, using the z-table, let's find p, the probability:

p (z = -1.48) = 0.0694

5. What sample mean (for a sample of size 20) would represent the bottom 15% (the 15th percentile)?

For p = 0.150, let's find the z-score:

z-score = - 2.17

z-score = X - μ/s.e

- 2.17 = (X - 67.7)/2.28

- 4.95 = X - 67.7

X = 67.7 - 4.95

X = 62.75 (rounding to the next hundredth)

The sample mean of 62.75 would represent the 15th percentile

7 0

2 years ago

Which equation has x=2/3 as a solution and why?

eduard

There are an infinite number of different equations that have
x=2/3 as the solution, or as one of several solutions.

You didn't show us your list of choices, so we can't help you
pick the right one.

Just take each choice, one at a time. Write ' 2/3 ' in place of 'x'
in each equation, and simplify everything. You'll wind up with
one equation that's true, and the others will say something that's
nonsense.

The one that's true is the one that has x=2/3 as its solution.

6 0

3 years ago