Answer:
We are given an area and three different widths and we need to determine the corresponding length and perimeter.
The first width that is provided is 4 yards and to get an area of 100 we need to multiply it by 25 yards. This would mean that our length is 25 yards and our perimeter would be 2(l + w) which is 2(25 + 4) = 58 yards.
The second width that is given is 5 yards and in order to get an area of 100 yards we need to multiply by 20 yards. This would mean that our length is 20 yards and our perimeter would be 2(l + w) which is 2(20 + 5) = 50 yards.
The final width that is given is 10 yards and in order to get an area of 100 yards we need to multiply by 10. This would mean that our length is 10 yards and our perimeter would be 2(l + w) which is 2(10 + 10) = 40 yards.
Therefore the field that would require the least amount of fencing (the smallest perimeter) is option C, field #3.
<u><em>Hope this helps!</em></u>
Answer:
Area of rectangle PLUM = 75.00 square units
Step-by-step explanation:
Since diagonal of rectangle divides the rectangle into two equal triangles,
Therefore, area of the rectangle PLUM = 2× area of triangle PLM
By the mean proportional theorem,
In ΔPLM,
AP² = AM × AL
6² = AM × 8
AM = 
AM = 4.5 units
Area of PLM = 
= 
= 
= 12.5 × 3
= 37.5 units²
Now area of rectangle PLUM = 2×37.5 = 75 units²
Therefore, area of the rectangle is 75.00 square units.
Answer:
OMG THANK YOU SO MUCH I NEEDED THIS SO MUCH FOR MY MATH TEST!!!!
Step-by-step explanation:
Answer: 4.012
Step-by-step explanation: Hope this helps! :)
I cant see the picture sorry
