1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ratling [72]
3 years ago
15

What is the next letter AZBYCXD

Mathematics
2 answers:
seropon [69]3 years ago
8 0
"W" is the next letter.. it took me a while to figure it out... :D
KATRIN_1 [288]3 years ago
7 0
The pattern goes like this...
(1st letter from the beginning),(1st letter from the end),(2nd letter from the beginning),(2nd letter from the end), etc.

So the next letter in the pattern should be W.
You might be interested in
Let $$X_1, X_2, ...X_n$$ be uniformly distributed on the interval 0 to a. Recall that the maximum likelihood estimator of a is $
Solnce55 [7]

Answer:

a) \hat a = max(X_i)  

For this case the value for \hat a is always smaller than the value of a, assuming X_i \sim Unif[0,a] So then for this case it cannot be unbiased because an unbiased estimator satisfy this property:

E(a) - a= 0 and that's not our case.

b) E(\hat a) - a= \frac{na}{n+1} - a = \frac{na -an -a}{n+1}= \frac{-a}{n+1}

Since is a negative value we can conclude that underestimate the real value a.

\lim_{ n \to\infty} -\frac{1}{n+1}= 0

c) P(Y \leq y) = P(max(X_i) \leq y) = P(X_1 \leq y, X_2 \leq y, ..., X_n\leq y)

And assuming independence we have this:

P(Y \leq y) = P(X_1 \leq y) P(X_2 \leq y) .... P(X_n \leq y) = [P(X_1 \leq y)]^n = (\frac{y}{a})^n

f_Y (Y) = n (\frac{y}{a})^{n-1} * \frac{1}{a}= \frac{n}{a^n} y^{n-1} , y \in [0,a]

e) On this case we see that the estimator \hat a_1 is better than \hat a_2 and the reason why is because:

V(\hat a_1) > V(\hat a_2)

\frac{a^2}{3n}> \frac{a^2}{n(n+2)}

n(n+2) = n^2 + 2n > n +2n = 3n and that's satisfied for n>1.

Step-by-step explanation:

Part a

For this case we are assuming X_1, X_2 , ..., X_n \sim U(0,a)

And we are are ssuming the following estimator:

\hat a = max(X_i)  

For this case the value for \hat a is always smaller than the value of a, assuming X_i \sim Unif[0,a] So then for this case it cannot be unbiased because an unbiased estimator satisfy this property:

E(a) - a= 0 and that's not our case.

Part b

For this case we assume that the estimator is given by:

E(\hat a) = \frac{na}{n+1}

And using the definition of bias we have this:

E(\hat a) - a= \frac{na}{n+1} - a = \frac{na -an -a}{n+1}= \frac{-a}{n+1}

Since is a negative value we can conclude that underestimate the real value a.

And when we take the limit when n tend to infinity we got that the bias tend to 0.

\lim_{ n \to\infty} -\frac{1}{n+1}= 0

Part c

For this case we the followng random variable Y = max (X_i) and we can find the cumulative distribution function like this:

P(Y \leq y) = P(max(X_i) \leq y) = P(X_1 \leq y, X_2 \leq y, ..., X_n\leq y)

And assuming independence we have this:

P(Y \leq y) = P(X_1 \leq y) P(X_2 \leq y) .... P(X_n \leq y) = [P(X_1 \leq y)]^n = (\frac{y}{a})^n

Since all the random variables have the same distribution.  

Now we can find the density function derivating the distribution function like this:

f_Y (Y) = n (\frac{y}{a})^{n-1} * \frac{1}{a}= \frac{n}{a^n} y^{n-1} , y \in [0,a]

Now we can find the expected value for the random variable Y and we got this:

E(Y) = \int_{0}^a \frac{n}{a^n} y^n dy = \frac{n}{a^n} \frac{a^{n+1}}{n+1}= \frac{an}{n+1}

And the bias is given by:

E(Y)-a=\frac{an}{n+1} -a=\frac{an-an-a}{n+1}= -\frac{a}{n+1}

And again since the bias is not 0 we have a biased estimator.

Part e

For this case we have two estimators with the following variances:

V(\hat a_1) = \frac{a^2}{3n}

V(\hat a_2) = \frac{a^2}{n(n+2)}

On this case we see that the estimator \hat a_1 is better than \hat a_2 and the reason why is because:

V(\hat a_1) > V(\hat a_2)

\frac{a^2}{3n}> \frac{a^2}{n(n+2)}

n(n+2) = n^2 + 2n > n +2n = 3n and that's satisfied for n>1.

8 0
3 years ago
Does anyone know this i need an answer asap btw its 8th grade work
vesna_86 [32]
Quadrilateral 2 will be parallel just like the first Quadrilateral. The shapes are the same and AD and BC are parallel on both shapes.
6 0
3 years ago
I need help ASAP ! Please
Ymorist [56]

Answer:

Step-by-step explanation: I hope you understand this better

7 0
2 years ago
Need help asap due tmr !!!
mezya [45]
Here! not sure if it's right but i'm pretty confident. boom

6 0
2 years ago
Read 2 more answers
Explain why the term of the expression are 2x and 8 not x and 8?
LuckyWell [14K]

Answer:

because 2x is a variable and 8 is just a constant......am i right or no

Step-by-step explanation:

<3 ya have a nice day you sweetie pie munchkins

7 0
3 years ago
Other questions:
  • HELP MEH PLZ IT MAY BE SIMPLE BUT IM DUMB
    11·1 answer
  • Simplify each expression by destributing. math problem&gt; 3(2y-7)
    11·1 answer
  • I would like to know the process for dis ive been struggling on them. i tried to ask the teacher but they made it more confusing
    13·1 answer
  • 5 units from ( negative 1, negative 2) what is the coordinate ( , negative 2) explain why
    8·1 answer
  • I need help please solve
    12·1 answer
  • 2,165.413 to the hundredth
    8·2 answers
  • You roll a die and flip three coins. find the number of possible outcomes.
    12·2 answers
  • Help 6.5.AP-23 There were 675 people in line for a rock concert. Only 486 people got into the concert. Select the percent of peo
    11·1 answer
  • I just need help graphing!
    5·1 answer
  • Which fraction is represented by point A on the number line?
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!