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anzhelika [568]
3 years ago
15

you are building a rectangular wading pool you want the area of the bottom to be 90 ft squared you want the length of the pool t

o be 3 ft longer than twice its width what will the dimensions of the pool be
Mathematics
1 answer:
Sindrei [870]3 years ago
5 0
L=2W+3, A=LW, using L from the first in the second gives you:

A=(2W+3)W

A=2W^2+3W, and we are told A=90 so

2W^2+3W=90

2W^2+3W-90=0

2W^2-12W+15W-90=0

2W(W-6)+15(W-6)=0

(2W+15)(W-6)=0, since W>0 for all real possibilities, 

W=6ft, and since L=2W+3

L=15ft

So the pool will be 6 ft wide by 15 ft long.
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Answer:

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Step-by-step explanation:

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Given:

Figure of similar triangles.

To find:

The value of x and the measure of NR.

Solution:

In triangle RST and RMN,

\angle SRT\cong \angle MRN              (Vertically opposite angles)

\angle RST\cong \angle RMN              (Alternate interior angles)

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We know that, corresponding sides of similar triangles are proportional.

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