Answer:
Yes it can
Step-by-step explanation:
To check wether it's a right angle triangle we need to apply the Pythagoras theorem
h^2= a^2 +b^2
Hypotenuse is always the longest side so
5^2 = 3^2 + 4^2
This is correct, so the triangle is a right angle triangle
Answer from Gauthmath
Answer:
Step-by-step explanation:
Okay, so I think I know what the equations are, but I might have misinterpreted them because of the syntax- I think when you ask a question you can use the symbols tool to input it in a more clear way, otherwise you can use parentheses and such.
Problem 1:
(x²)/4 +y²= 1
y= x+1
*substitute for y*
Now we have a one-variable equation we can solve-
x²/4 + (x+1)² = 1
x²/4 + (x+1)(x+1)= 1
x²/4 + x²+2x+1= 1
*subtract 1 from both sides to set equal to 0*
x²/4 +x^2+2x=0
x²/4 can also be 1/4 * x²
1/4 * x² +1*x² +2x = 0
*combine like terms*
5/4 * x^2+2x+ 0 =0
now, you can use the quadratic equation to solve for x
a= 5/4
b= 2
c=0
the syntax on this will be rough, but I'll do my best...
x= (-b ± √(b²-4ac))/(2a)
x= (-2 ±√(2²-4*(5/4)*(0))/(2*(5/4))
x= (-2 ±√(4-0))/(2.5)
x= (-2±2)/2.5
x will have 2 answers because of ±
x= 0 or x= 1.6
now plug that back into one of the equations and solve.
y= 0+1 = 1
y= 1.6+1= 2.6
Hopefully this explanation was enough to help you solve problem 2.
Problem 2:
x² + y² -16y +39= 0
y²- x² -9= 0
Answer:
Step-by-step explanation:
How do we find the line that's perpendicular to another?
We find the negative reciprocal. So for example if our slope is 2, the negative reciprocal would be .
Answer: Yes the sum of any two numbers is greater than the larger of the two numbers.
Step-by-step explanation:
Yes the sum of any two numbers is greater than the larger of the two numbers.
Let us assume that the two numbers are a and b and ab is the number.
a + b > a
b > a – a
b > 0
This therefore implies that b > 0.
This may however not be true when the value of b is zero(0) or a negative number.
