Given: ∠AOB is a central angle and ∠ACB is a circumscribed angle. Prove: △ACO ≅ △BCO Circle O is shown. Line segments A O and B

Question

3 years ago

11

Given: ∠AOB is a central angle and ∠ACB is a circumscribed angle. Prove: △ACO ≅ △BCO Circle O is shown. Line segments A O and B

O are radii. Tangents C B and C B intersect at point C outside of the circle. A line is drawn to connect points C and O. We are given that angle AOB is a central angle of circle O and that angle ACB is a circumscribed angle of circle O. We see that AO ≅ BO because . We also know that AC ≅ BC since . Using the reflexive property, we see that . Therefore, we conclude that △ACO is congruent to △BCO by the .

Mathematics

2 answers:

charle [14.2K] · Answer 1 · 2022-05-05T10:18:45+03:00

charle [14.2K]3 years ago

6 0

Answer:

all radii of the same circle are congruent

tangents to a circle that intersect are congruent

side CO is congruent to side CO

SSS congruency theorem

Step-by-step explanation:

m_a_m_a [10] · Answer 2 · 2022-05-05T11:26:38+03:00

m_a_m_a [10]3 years ago

6 0

Answer:

1,3,3,1

Step-by-step explanation:

Trust the process

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