A=g≈-32
v=⌠a dt since a≈-32
v=-32t+C, where C is the initial velocity, which we are told is 20 ft/s
v=-32t+20
h=⌠v dt
h=-32t^2/2+20t+C, where C is the initial height, so what is a reasonable initial height? How about 3 ft since we are swinging a bat around maybe our waist level... maybe :P
h=-16t^2+20t+3
Your choices may have made a different assumption about the initial height of course but you did not show your choices, but certainly it will be:
h(t)=-16t^2+20t+hi, where hi is the initial height in feet.
This of course ignores air resistance and flight dynamics of a spinning ball with seams, which will make a significant difference in real life :)
Answer:
C
Step-by-step explanation:
Answer:
Given,
mass of snow flake = 2 kg
mass of midnight = 997 gm
Now,
1 kg = 1000 gm
2 kg = 1000 * 2
= 2000 gm
therefore the difference between the masses of the kittens = 2000
- 997
= 1003 gm (is the answer)
Answer:
22 posts
Step-by-step explanation:
on the side of 20 feet you have 5 fence posts each in including one on each of the corners. On the 35 feet side you would have 8 including the corners, but since the corner posts are done its 6 on each 35 feet side. So you get 5+5+6+6=22
Answer:
1623623
Step-by-step explanation:
i just got this question on deltamath lol
