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natulia [17]
4 years ago
6

If you were in a freely falling elevator and you dropped a pencil. it would hover in front of you. Is there a force of gravityac

ting on the pencil? Defend your answer.
Physics
1 answer:
11111nata11111 [884]4 years ago
7 0

Answer:Yes

Explanation:

Yes, there will be a force of gravity acting on the Pencil but it will hover in front of the person because lift would itself having free fall.  

Free is the state of body where gravity is the only force acting on the body while it is falling from a height.

According to the theory of relativity, a body under free fall has no force acting on it.

Anything inside the lift will be experiencing the free fall as they are falling under the influence of gravity completely.

 

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Use the data provided to calculate the gravitational
nydimaria [60]

Answer:

3 kg:   14.7 kJ

6 kg:   29.4 kJ

9 kg:  44.1 kJ

Explanation:

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8 0
4 years ago
A businesswoman is rushing out of a hotel through a revolving door with a force of 80 N applied at the edge of the 3 m wide door
mel-nik [20]

Answer:

Explanation:

Given

Force applied F=80\ N

Door is d=3\ m wide

for gate to revolve Properly Pivot Point must be at center i.e. 1.5 from either end

Torque applied is T=force\times distance

Maximum torque

T_{max}=F\times \frac{d}{2}

T_{max}=80\times \frac{3}{2}

T_{max}=120\ N-m

7 0
3 years ago
A baseball pitcher loosens up his pitching arm. He tosses a 0.20-kg ball using only the rotation of his forearm, 0.28 m in lengt
gayaneshka [121]

Answer:

Moment of Inertia, I = 0.016 kgm²

Explanation:

Mass of the ball, m = 0.20 kg

Length of the pitcher's arm, l = 0.28

Radius of the circular arc, r = 0.28 m

Moment of Inertia is given by the formula:

I = mr²

I = 0.20 * 0.28²

I = 0.20 * 0.0784

I = 0.01568

I = 0.016 kgm²

5 0
4 years ago
A(n) 1100 kg car is parked on a 4◦ incline. The acceleration of gravity is 9.8 m/s 2 . Find the force of friction keeping the ca
igomit [66]

Answer:

Force of friction, f = 751.97 N

Explanation:

it is given that,

Mass of the car, m = 1100 kg

It is parked on a 4° incline. We need to find the force of friction keeping the car from sliding down the incline.

From the attached figure, it is clear that the normal and its weight is acting on the car. f is the force of friction such that it balances the x component of its weight i.e.

f=mg\ sin\theta

f=1100\ kg\times 9.8\ m/s^2\ sin(4)

f = 751.97 N

So, the force of friction on the car is 751.97 N. Hence, this is the required solution.

3 0
3 years ago
Find the magnitude of the net electric force exerted on this charge. Express your answer in terms of some or all of the variable
Yuri [45]

Answer:

Th steps is as shown in the attachment

Explanation:

from the diagram, its indicates that twelve identical charges are distributed evenly on the circumference of the circle. assuming one of gthe charge is shifted to the centre of he circle alomng the x axis, as such the charge is unbalanced and there is need ot balanced all the identical charges for the net force to be equal to zero.

The mathematical interpretation is as shown in the attachment.

3 0
3 years ago
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