Answer:
Explanation:
Given
Force applied 
Door is
wide
for gate to revolve Properly Pivot Point must be at center i.e. 1.5 from either end
Torque applied is
Maximum torque



Answer:
Moment of Inertia, I = 0.016 kgm²
Explanation:
Mass of the ball, m = 0.20 kg
Length of the pitcher's arm, l = 0.28
Radius of the circular arc, r = 0.28 m
Moment of Inertia is given by the formula:
I = mr²
I = 0.20 * 0.28²
I = 0.20 * 0.0784
I = 0.01568
I = 0.016 kgm²
Answer:
Force of friction, f = 751.97 N
Explanation:
it is given that,
Mass of the car, m = 1100 kg
It is parked on a 4° incline. We need to find the force of friction keeping the car from sliding down the incline.
From the attached figure, it is clear that the normal and its weight is acting on the car. f is the force of friction such that it balances the x component of its weight i.e.


f = 751.97 N
So, the force of friction on the car is 751.97 N. Hence, this is the required solution.
Answer:
Th steps is as shown in the attachment
Explanation:
from the diagram, its indicates that twelve identical charges are distributed evenly on the circumference of the circle. assuming one of gthe charge is shifted to the centre of he circle alomng the x axis, as such the charge is unbalanced and there is need ot balanced all the identical charges for the net force to be equal to zero.
The mathematical interpretation is as shown in the attachment.