Answer:
The AC generator has one unbroken slip ring
Explanation:
In physics, the application of electromagnetic induction can be seen in generators and dynamos. Electromagnetic induction is the process of generating electricity using magnets. It found applications in generators and the types of generator they found application is in AC and DC generator.
An AC generator is also called a Dynamo. A DC generator contains what is called a SPLIT RING fixed to the end of the coil which can be separated and coupled back according to the name "split". An AC generator also called a Dynamo makes use of a SLIP ring which cannot be divided into two. It comes as an entity. The presence of this rings is what differentiates a DC generator from an AC generator.
We can replace split rings with slip rings when converting a DC generator to an AC generator and vice versa.
It can therefore be concluded that the difference between a DC and an AC generator is that the AC generator has one unbroken slip ring.
Answer:
shrinks with all the fringes getting narrower
Explanation:
As the light passes through the slit, the diffraction pattern shrinks, as the waves have more opening to penetrate, and the fringes becomes more narrow as a result of that, The opposite happens as the conditions are reversed.
Answer:
V = 48.4m/s, θ = 73.6° below the horizontal.
Explanation:
Given h = 109.53m, x = range = 65m,
θ = 0°
This problem involves the concepts of projectile motion.
Let yo = h = 109.53m
y = final position on the y axis. = 0m (ground level)
y = yo + vosinθ – 1/2gt²
0 = 109.53 + vosin0° – 1/2×9.8×t²
0 = 109.53 – 4.9t²
4.9t² = 109.53
t² = 109.53/4.9 = 22.35
t = √22.35 = 4.73s
So it takes the ball t = 4.73 seconds to get to the ground from the launch point.
x = (vocosθ)×t
65 = (vocos0°)×4.73
65/4.73 = vo
Vo = 13.7m/s
Vx = Vox = Vocosθ = 13.7cos0° = 13.7m/s
Vy = Voy – gt = Vosinθ – gt
Vy = 13.7sin0° – 9.8×4.73 = –46.4m/s
V = √(Vy² + Vx²) = √(-46.4² + 13.7²)
V = 48.4m/s
θ = Tan-¹(vy/vx) = tan-¹(-46.4/13.7) = -73.6°
θ = 73.6° below the horizontal
V = 48.4m/s
A) The average translational kinetic energy of the molecules in a gas is given by:
where
is the Boltzmann's constant
T is the absolute temperature of the gas
In our problem,
, so the average translational kinetic energy of the molecules is
We have 1.2 mol of this gas, and since one mole of ideal gas contains a number of molecules equal to Avogadro number, the total number of molecules in our gas is
So the total translational kinetic energy of all molecules of the gas is
B) The kinetic energy of a person is given by:
where m is the person's mass and v his velocity. The person has a mass of m=75 kg and its energy is equal to the energy of the gas,
, therefore his velocity must be