Answer:
Orbital Eccentricity
Planet Orbital Eccentricity
(Point in Orbit Closest to Sun)
measured in AU's
Mercury 0.206
Venus 0.007
Earth 0.017
Mars 0.093
Jupiter 0.048
Saturn 0.056
Uranus 0.047
Neptune 0.009
Pluto 0.248
Explanation:
link to information:
https://www.enchantedlearning.com/subjects/astronomy/glossary/Eccentricity.shtml
Answer:
Decreases
Explanation:
Force= mass * acceleration
If the mass increases but force stays the same then the acceleration would have to decrease to maintain the same force
To develop this point we will start by finding the approximate coordinates of the points that were connected at the time of the Pangaea between Brazil and Angola. These coordinates are presented below.
1 . Brazil - Latitude: 18 0 07’ 55.56” S Longitude: 39 0 35’ 14.50” W 2.
Angola - Latitude: 9 0 08’ 50.02” S Longitude: 13 0 02’ 32.11” E
Using a tool for calculating distances between these two points we will notice that its distance is 576,155,570.12 cm
Applying the equation given in the statement we will have to,

200,000,000 years have passed and the movement was previously found, so the speed of travel is,


Therefore the velocity is 2.88 cm per year.
Answer:
Velocity of the projectile just before it will hit the surface is 43.4 m/s
Explanation:
In x direction there is no acceleration
so horizontal velocity of the projectile is always constant
So we have

now in Y direction its motion is free fall motion under gravity
so we have


so we have



From the given graph,
If the distance is on the y-axis and time is on the x-axis
Then in the given graph, curve A has a negative slope while curve C and line B has a positive slope. This proves that the behavior of x & y is inversely proportional to each other.
Now, from the graph, line drown from curve A will be inversely proportional to the line B.
Hence, the second option A will be the correct option.