Ask question

Ask question

All categories

3 years ago

15

If you are about to be hit from behind? Your best course of action isto brake gently and stop the car.

1 answer:

Archy [21]3 years ago

3 0

True but it depends on how far the other person is 2 u

You might be interested in

Three boxes rest side-by-side on a smooth, horizontal floor. Their masses are 5.0 kg, 3.0 kg, and 2.0 kg, with the 3.0-kg mass i

Fed [463]

Answer:25 N

Explanation:

Given

mass of 5 , 3 & 2 kg blocks lie on floor

Force on 50 N pushes the 5 kg box

$Let N_1$ be the reaction on 2 kg box therefore

$N_1=2\times a$

where a is the acceleration of the system

$N_2=$ reaction on 3 kg block by 5 kg block

$N_2-N_1=3a$

$N_2=5a$

Now for 5 kg block

$F-N_2=5a$

F=10a

$a=\frac{F}{10}=5 m/s^2$

Force exerted by 5 kg block on 3 kg block is

$N_2=5\times 5=25 N$

6 0

3 years ago

Examples of how thermal energy transfer by conduction, convection, or radiation.

____ [38]

Microwave Radiation. Microwave radiation utilizes short, high-frequency waves that penetrate food, which agitates its water molecules to create friction and transfer heat. If you're heating a solid substance, this heat energy is transferred throughout the food through conduction, while liquids do so through convection.

3 0

3 years ago

When light shines on a metal surface, the maximum energies of emitted electrons:

SVEN [57.7K]

Vary with the frequency of the light

4 0

3 years ago

Newton’s law of cooling states that dx dt = −k(x−A) where x is the temperature,t is time, A is the ambient temperature, and k &g

lys-0071 [83]

Answer:

a) $X= kA_o\dfrac{1}{k^2+\omega^2}\left ( kcos\omega t+\omega sin\omega t \right )+Ce^{-kt}$

b)Does not affect the long term.

Explanation:

Given that

$\dfrac{dx}{dt}=-k(x-A)$

A = A0 cos(ωt)

$\dfrac{dx}{dt}=-k(x-A_o cos(\omega t))$

$\dfrac{dx}{dt}+kx=kA_o cos(\omega t)$

This is linear equation so integration factor ,I

$I=e^{\int kdt}$

$I=e^{kt}$

Now by using linear equation property

$e^{kt} X=\int e^{kt} kA_o cos(\omega t) dt +C$

$e^{kt} X= kA_o \dfrac{e^{kt}}{k^2+\omega^2}\left ( kcos\omega t+\omega sin\omega t \right )+C$

$X= kA_o\dfrac{1}{k^2+\omega^2}\left ( kcos\omega t+\omega sin\omega t \right )+Ce^{-kt}$

b)

at t= 0

$X(0)=\dfrac{k^2A_o}{\omega^2+k^2}+C$

$X= kA_o\dfrac{1}{k^2+\omega^2}\left ( kcos\omega t+\omega sin\omega t \right )+e^{-kt}\times \left ( X(0)-\dfrac{k^2A_o}{\omega^2+k^2} \right )$

So the initial condition does not affect the long term.

5 0

4 years ago

Which of the following is NOT an example of work?

marysya [2.9K]

I think the answer is c.<span>holding a tray in the cafeteria line</span>

3 0

4 years ago