$\text{Use the distance formula: }d_AB=\sqrt{(x_A-x_B)^2+(y_A-y_B)^2}\\where\ (X_A, y_A)=(-3, -2)\\and\ (x_B,y_B)=(4, -7)\\\\\\d_AB=\sqrt{(-3-4)^2+[-2-(-7)]^2}\\\\.\quad =\sqrt{(-7)^2+(5)^2}\\\\.\quad =\sqrt{49+25}\\\\.\quad =\boxed{\sqrt{74}}$

3 0

3 years ago

Which relationship has a zero slope

vesna_86 [32]

Answer:

The first table.

Step-by-step explanation:

A slope of 0 means that as x increases, y stays the same. In the first table, all of our y-values are 2; this means that y stays constant.

To prove it, we use our formula for slope:

$m=\frac{y_2-y_1}{x_2-x_1}$

The slope of the line between the first two points is

(2-2)/(-3--1) = 0/-2 = 0

The slope of the line between the second pair of points is

(2-2)/(-1-1) = 0/-2 = 0

The slope of the line between the next pair of points is

(2-2)/(1-3) = 0/-2 = 0

Since the slope between each pair of points is 0, the slope of the entire line is 0.

4 0

3 years ago

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