Equation of line passing through (2, -2) and parallel to 2x+3y = -8 is 
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Need to write equation of line parallel to 2x+3y=-8 and passes through the point (2, -2)
Generic slope intercept form of a line is given by y = mx + c
where "m" = slope of the line and "c" is the y - intercept
Let’s first find slope intercept form of 2x+3y=-8 to get slope of line

On comparing above slope intercept form of given equation with generic slope intercept form y = mx + c,

We know that slopes of parallel lines are always equal
So the slope of line passing through (2, -2) is also 
Equation of line passing through
and having slope of m is given by


Substituting the values in equation of line we get



Hence equation of line passing through (2 , -2) and parallel to 2x + 3y = -8 is given as 
Answer:
x=12
Step-by-step explanation:
LM + MN = LN
2x-16 + x-9 = 11
Combine like terms
3x-25=11
Add 25 to each side
3x-25+25 = 11+25
3x = 36
Divide by 3
3x/3=36/3
x = 12
Answer:
m C and m D are a linear pair // Definition of supplementary angles
m C + m D =180 // Definition of a linear pair
Step-by-step explanation:
9514 1404 393
Answer:
61.4
Step-by-step explanation:
The length of two semicircles of diameter 10 is the circumference of a circle of that diameter:
C = πd = 10π ≈ 31.4
The perimeter includes that length plus the lengths of two straight sides that are 15 units each.
P = 31.4 + 2×15
P = 61.4 . . . . units
The answer is 2.6 because 2.6+2=4.6