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Anon25 [30]
3 years ago
14

triangle ABC has vertices A (0,2), B (4,4), and C (-1,4). what are the vertices of its image with a scale factor of 4?

Mathematics
1 answer:
Aneli [31]3 years ago
6 0
Hope that I answer your question

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What are the correct answers and why? Simple and concise explanation please!!!
dezoksy [38]

Answer:

\large\boxed{-\bigg[(x-3)^2+2x\bigg]+1}\\\\\boxed{-x^2+4x-8}

Step-by-step explanation:

(g\ \circ\ f)(x)=g\bigg(f(x)\bigg)

f(x)=(x-3)^2+2x\\\\g(x)=-x+1\\\\g\ \circ\ f\to\text{put f(x) instead of x in the function g(x)}:\\\\(g\ \circ\ f)(x)=-\bigg[\underbrace{(x-3)^2+2x}_{x}\bigg]+1

-----------------------------------------

-\bigg[(x-3)^2+2x\bigg]+1=-(x-3)^2-2x+1\\\\\text{use}\ (a-b)^2=a^2-2ab+b^2\\\\=-(x^2-(2)(x)(3)+3^2)-2x+1=-(x^2-6x+9)-2x+1\\\\=-x^2-(-6x)-9-2x+1=-x^2+6x-9-2x+1\\\\\text{combine like terms}\\\\=-x^2+(6x-2x)+(-9+1)=-x^2+4x-8

-----------------------------------

-x^2+4x-8=-x^2+4x-2^2+2^2-8=-(x^2-4x+2^2)+4-8\\\\=-(\underbrace{x^2-(2)(x)(2)+2^2}_{(a-b)^2=a^2-2ab+b^2})-4=-(x-2)^2-4=-(x+1-3)^2-4

In\ (-x+1-3)^2+2x,\ x^2\ will\ be\ positive.\\In\ (-x+1-3)^2+2(-x+1),\ x^2\ will\ be\ positive.

6 0
2 years ago
Read 2 more answers
Solve for y: 4y = 32 A. y = 4 B. y = 6 C. y = 8 D. y = 9
I am Lyosha [343]

Answer:

C

Step-by-step explanation:

4y=32

Taking 4 to the other side

y=32/4

y=8

6 0
3 years ago
Read 2 more answers
Solve vertex form out <br> О=x^2 -4x -12
pochemuha

Answer:  (2,-16)

Step-by-step explanation: you have to rewrite it by using the vertex form (h,k)

3 0
3 years ago
0.139 times what number could get me to 100? PLEASE ANSWER, FAST
Triss [41]

Answer:

719.4244604

Step-by-step explanation:

100/0.139=719.4244604

7 0
3 years ago
A jet climbs at a steady rate at an angle of inclination of 0.5 degree during game off what will its he height be after a 2.2 km
Aneli [31]
A right triangle will be formed with 2.2 km as the hypotenuse, 0.5 degrees as the angle, and an unknown height (see attachment).

Recall the trigonmetric ratios sine, cosine, and tangent that can be used for right triangles.
Sin<span>θ = opposite side/hypotenuse
</span>Cos<span>θ = adjacent side/hypotenuse
</span>tan<span>θ = opposite side / adjacent side
</span>θ (theta) refers to the angle (not the right angle). In this case, θ is the given angle of 0.5°.

In this problem, you will use sine because there is a side opposite to the angle (the unknown side h) and the hypotenuse, and sine relates those two sides.

Let the variable h represent the unknown opposite side, the height.
sin(0.5°) = h / (2.2km)
h = (2.2km)sin(0.5<span>°)
h = 0.019 km

Hope I helped! If you have questions on any of the steps, please comment below.</span>

3 0
3 years ago
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