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vladimir1956 [14]
3 years ago
6

Answer to [4x 42]=[24 6y] matrices

Mathematics
1 answer:
sergij07 [2.7K]3 years ago
4 0

The x and y values in the given matrices are 6 and 7 respectively.

Step-by-step explanation:

Step 1; Both the given matrices are of the order 1 × 2. So to solve the values of x and y is just a matter of substitution. We substitute the values which correspond with each other i.e we substitute the values of a_{11} which is the element at row 1 column 1 of both matrices. Similarly, the values of a_{12} in both matrices are substituted with each other.

Step 2; The value of a_{11} of the first matrix is 4x and the corresponding value in the second matrix is 24. So 4x will be equal to 24. Similarly, the value of a_{12} in the second matrix is 6y and its corresponding value in the first matrix is 42. So 6y will equal 42.

4x = 24, x = \frac{24}{4}, x = 6

6y = 42, y = \frac{42}{6}, y = 7

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marin [14]

Answer:

MNK = TRP

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X = 6.3

Step-by-step explanation:

MNK is congruent to TRP because the two triangles are congruent, which is a given statement. This also means that all side and angle measures will be congruent. Because of this, it can be inferred that MN is congruent to TR and they have equal side length measures. This means that TR measures 20. This means that 3X - 1 = 20. By solving we can get 6.33.

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3 years ago
Its easy please ill give brainiest dont guess
valentina_108 [34]

Answer:

I don't know

Step-by-step explanation:

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Rus_ich [418]
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3 years ago
The volume of a right cylinder is V = πr2h. If we have an oblique cylinder, like in the figure, what is the volume of a cross-se
olchik [2.2K]
Since you did not attach any picture we cannot say for sure what is the correct answer, but we can discuss the options in order to find the most probable correct answer.

First of all, according to the Cavalieri's principle, an oblique cylinder has the same volume as a right cylinder with the same base surface area and same height.
A cross-section of an oblique cylinder will be a small right cylinder with the same base surface area and a height as small as possible.

I guess the oblique cylinder has height h and it is divided into many (probably 10) cross-sections.

Option A: <span>πr2h
This is exactly the volume of the right cylinder, therefore, unless you are given a cross-section of height h (which would be too easy), this won't be the correct answer.

Option B: </span><span>4πr2h
This is 4 times the right cylinder. Again, here the height of the cross-section should</span> be 4h, but it doesn't sound like a possible data (too easy again).

Option C: <span>1 10 πr2h
Here comes a n issue with the notation: I think the right number you meant to write is (1/10)</span>·πr2h and not 110·<span>πr2h.
If I am right, this means that your oblique cylinder of height h is divided into 10 cross-sections, and therefore the volume of each of these cross-sections will be a tenth of the volume of the oblique cylinder, which means </span>1/10·<span>πr2h.

Option D: </span><span>1 2 πr2h
Here, we have the same notation issue as before. I think you meant (1/2)</span>·<span>πr2h.
Here, your oblique cylinder height h should be divided into only 2 cross-sections. Now, we said the cross-section's height should be the smallest as possible, so an oblique cylinder divided only into two pieces doesn't sound good.

Therefore, the most probable correct answer will be C) </span>(1/10)·<span>πr2h</span>
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3 years ago
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elena55 [62]

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