Answer:
ln (m^2n^9)
Step-by-step explanation:
Rule: ln a + ln b = ln ab
Rule: ln a^n = n * ln a
2 ln m + 9 ln n =
= ln m^2 + ln n^9
= ln (m^2n^9)
= 
Answer:
1716 ;
700 ;
1715 ;
658 ;
1254 ;
792
Step-by-step explanation:
Given that :
Number of members (n) = 13
a. How many ways can a group of seven be chosen to work on a project?
13C7:
Recall :
nCr = n! ÷ (n-r)! r!
13C7 = 13! ÷ (13 - 7)!7!
= 13! ÷ 6! 7!
(13*12*11*10*9*8*7!) ÷ 7! (6*5*4*3*2*1)
1235520 / 720
= 1716
b. Suppose seven team members are women and six are men.
Men = 6 ; women = 7
(i) How many groups of seven can be chosen that contain four women and three men?
(7C4) * (6C3)
Using calculator :
7C4 = 35
6C3 = 20
(35 * 20) = 700
(ii) How many groups of seven can be chosen that contain at least one man?
13C7 - 7C7
7C7 = only women
13C7 = 1716
7C7 = 1
1716 - 1 = 1715
(iii) How many groups of seven can be chosen that contain at most three women?
(6C4 * 7C3) + (6C5 * 7C2) + (6C6 * 7C1)
Using calculator :
(15 * 35) + (6 * 21) + (1 * 7)
525 + 126 + 7
= 658
c. Suppose two team members refuse to work together on projects. How many groups of seven can be chosen to work on a project?
(First in second out) + (second in first out) + (both out)
13 - 2 = 11
11C6 + 11C6 + 11C7
Using calculator :
462 + 462 + 330
= 1254
d. Suppose two team members insist on either working together or not at all on projects. How many groups of seven can be chosen to work on a project?
Number of ways with both in the group = 11C5
Number of ways with both out of the group = 11C7
11C5 + 11C7
462 + 330
= 792
Answer:
600:450:450
Step-by-step explanation:
8+6+6= 20
1500/20=75
8*75= 600
6*75= 450
6*75=450
Check:
600/75= 8
450/75= 6
450/75=6
Step-by-step explanation:
On the first question, you would want to put the equation together. To find x you will put 2x+6=40. Subtract 6 on both sides and you will find your x value.
Answer:
Mode: 5 and 8
Median: 6.5
Step-by-step explanation:
Mode - the number that appears the most in a set of data. There may be no mode ( when no number out numbers the others) or multiple modes ( multiple numbers appear the same number of times). Both 5 and 8 appear twice in this set.
Median - The middle number. To start, order your numbers from least to greatest.
1, 3, 5, 5, 8, 8, 10, 14
You have an even set of numbers (8 in total), which means there won't be one number left in the middle. In this situation, there are two: 5 and 8. So you just need to add them together and divide by 2
8 + 5 = 13
13/ 2 = 6.5
