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fredd [130]
3 years ago
7

What is the distance (3,9) and (12,21)

Mathematics
2 answers:
VMariaS [17]3 years ago
7 0
6 and 8 I think I’m not sure
eimsori [14]3 years ago
4 0

d = 15.

The easiest way to calculate the distance between two point in the space is usign the equation d = √(x₂-x₁)²+(y₂-y₁)².

The distance between the points (3, 9) and (12, 21) is:

d = √(12-3)²+(21-9)² = √(9)²+(12)² = √81+144 = √225 = 15

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Evaluate f(x) = 2x at x = 5.<br> A) 32<br> B) 10<br> C) 64<br> D) 25
maks197457 [2]

Answer:

A is the answer 32

Step-by-step explanation:

use a digital calculator or a scientific

7 0
3 years ago
which polynomial represents the sum below? (3x^2+3) + (3x^2+x+4) A) 6x^2+x+12 B) 9x^2+x+7 C) 6x^@+x+7 d)9x^2+x+12
mezya [45]

Answer:

Step-by-step explanation:

3x^2 + 3 + 3x^2 + x + 4....combine like terms

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4 0
3 years ago
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Diano4ka-milaya [45]
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5 0
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Evgesh-ka [11]
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6 0
3 years ago
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F(x) = x^2 + 4x + 20 find the real roots. take your time if you want :)
s344n2d4d5 [400]

Answer:

No real roots

x = -2 + 4i, x = -2 - 4i

Step-by-step explanation:

Hello!

We can solve the quadratic by using the Quadratic Formula.

Standard form of a Quadratic: ax^2 + bx + c = 0

Quadratic Equation: x = \frac{-b\pm\sqrt{b^2 - 4ac}}{2a}

Given our Equation: f(x) = x^2 + 4x + 20

  • a = 1
  • b = 4
  • c = 20

Set the equation to 0 and solve using the formula.

<h3>Solve</h3>
  • x = \frac{-b\pm\sqrt{b^2 - 4ac}}{2a}
  • x = \frac{-4\pm\sqrt{4^2 - 4(1)(20)}}{2(1)}
  • x = \frac{-4\pm\sqrt{16 - 80}}{2}
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There are no real roots to the quadratic.

8 0
2 years ago
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