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4 years ago

BEST ANSWER GETS BRAINLIEST!! PLEASE HELP

1 answer:

defon4 years ago

6 0

Part A:
3(10m +5)
3m + 15 + 27m

Part B:
3m + 15 + 27m = 3(m + 5 + 9m) ....factor
using distributive property

Part C:
let m = 1

3(10m +5)
= 3[(10(1)+5]
=3(10+5)
=3(15)
=45

3(m + 5 + 9m)
= 3[(1+5 + 9(1)]
=3(1+5+9)
=3(15)
=45

both are equilvalent

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