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1 answer:
<span>Part A:
3(10m +5)
3m + 15 + 27m
</span><span>Part B:
</span>3m + 15 + 27m = 3(<span>m + 5 + 9m) ....factor
using distributive property
Part C:
let m = 1
</span>3(10m +5)
= 3[(10(1)+5]
=3(10+5)
=3(15)
=45
<span>3(m + 5 + 9m)
</span>= 3[(1+5 + 9(1)]
=3(1+5+9)
=3(15)
=45
both are equilvalent
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