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3 years ago

Helppppppppppppppppppppppppppppp

Mathematics

1 answer:

GalinKa [24]3 years ago

7 0

Answer:
x = 4

Explanation:
For the right hand side:
log base 9 of 8 + log base 9 of (x-2) = log base 9 (8*(x-2))
= log base 9 of (8x-16)
For the left hand side:
2*log base 9 of x = log base 9 of x^2

Now, equating the two sides and solving for x:
log base 9 of (8x-16) = log base 9 of x^2
This means that:
x^2 = 8x - 16
x^2 - 8x + 16 = 0
(x-4)^2 = 0
Therefore:
x = 4

Hope this helps :)

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$p=\frac{x}{n}=\frac{20}{309}=0.065$

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np ≥ 10
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Hence, the conditions are fulfilled.

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$p=N(p, \frac{p(1-p)}{n})$

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3 years ago

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Step-by-step explanation:

Perhaps you're concerned with the sequence ...

{2, -24/9, 120/27, -720/81, ...}

1. This is neither arithmetic nor geometric. Ratios of terms are -4/3, -5/3, -6/3.

The alternating signs mean one factor of the general term is (-1)^(n-1). The divisors of 3 in the term ratios indicate 3^-n is another factor. The increasing multipliers suggest that a factorial is involved.

If we rewrite the sequence factoring out (-1)^(n-1)/3^n, we have ...

{6, 24, 120, 720, ...}

corresponding to 3!, 4!, 5!, 6!. This lets us conclude the remaining factor is (n+1)!.

The general term is ...

$\boxed{a_n=\dfrac{(-1)^{n-1}(n+2)!}{3^n}}$

2. The magnitude of the factorial quickly outstrips the magnitude of the exponential denominator, so the terms keep getting larger and larger.

The sequence diverges.

3. No series are provided.

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3 years ago